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Tju [1.3M]
3 years ago
15

Which literal equations are equivalent to p = mv?

Mathematics
1 answer:
anygoal [31]3 years ago
7 0
B and D because it doesnt matter how you write the equation you still get the same answer, 

don't forget to rate my answer 5 stars and thank me
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Write a polynomial that represents the area of the shaded region
marusya05 [52]
<h3>Answer: x^2-3x+36</h3>

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Explanation:

The larger rectangle has area of (x+1)(x+1) = x^2+2x+1 through the use of the FOIL rule or distribution

If you use distribution, then it might help to let y = x+1 so we'd have y(x+1) lead to xy+1y which becomes x(x+1)+1(x+1). From there it might be easier to see how to get x^2+2x+1 after everything distributes again and simplifies.

The smaller rectangle has area 5x-35 which is found by distributing 5(x-7)

To get the shaded area, we subtract the two rectangle areas found above

shaded area = (larger area) - (smaller area)

shaded area = (x^2+2x+1) - (5x - 35)

shaded area = x^2+2x+1 - 5x + 35

shaded area = x^2-3x+36

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3 years ago
Historically, the average time to service a customer complaint has been 3 days and the standard deviation has been 0.50 day. Man
kicyunya [14]
Oof I didn’t learn about this you can ask a class and go over it
6 0
3 years ago
PLEASE HELP I PROMISE I WILL MARK BRAINLIEST IF RIGHT ASAP.
Roman55 [17]

Answer:

1.8

Step-by-step explanation:

5 0
3 years ago
I need Help with this (Solving Equations with Efficiency) Topic:
luda_lava [24]
There is no solution
8 0
3 years ago
Shown here are four frequency distributions. Each is incorrectly constructed. State the reason why.
Tanya [424]

Answer/Step-by-step explanation:

a. The the class width for the 1st, 2nd, 3rd, and 5th row equal 5 in the frequency distribution. Whereas, in the 4th row, the class width is 4 (49 - 45). This makes the construction incorrect.

b. Here, the upper limit of each consecutive class was used as the lower limit if the next class. For example, 9 is a member of the first class, which is the upper limit if the class in the first row, it ought not to be included as a member of the next class in the second row.

c. In the 3rd row, the lower limit of the class should be 133, NOT 138.

d. Different class width were used.

Row 1 class width = 13 - 9 = 4

Row 2 class width = 19 - 14 = 5

Row 3 class width = 25 - 20 = 5

Row 4 class width = 28 - 26 = 2

Row 5 class width = 32 - 29 = 3

8 0
3 years ago
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