X+3, -2x^(2)-6x, 4x^(3)+12x^(2) what is the 8th term in this geometric sequence
1 answer:
Answer:
a8 = -128x^8 -384x^7
Step-by-step explanation:
The formula for the general term of a geometric sequence with first term a1 and common ratio r is ...
an = a1·r^(n-1)
Here, we have a1 = (x+3) and r = (-2x^2-6x)/(x+3) = -2x. Then the 8th term is ...
a8 = (x+3)(-2x)^(8-1)
a8 = -128x^8 -384x^7
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