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Furkat [3]
3 years ago
9

X+3, -2x^(2)-6x, 4x^(3)+12x^(2) what is the 8th term in this geometric sequence

Mathematics
1 answer:
seraphim [82]3 years ago
4 0

Answer:

  a8 = -128x^8 -384x^7

Step-by-step explanation:

The formula for the general term of a geometric sequence with first term a1 and common ratio r is ...

  an = a1·r^(n-1)

Here, we have a1 = (x+3) and r = (-2x^2-6x)/(x+3) = -2x. Then the 8th term is ...

  a8 = (x+3)(-2x)^(8-1)

  a8 = -128x^8 -384x^7

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Answer:

The unusual X values ​​for this model are: X = 0, 1, 2, 7, 8

Step-by-step explanation:

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P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024

P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215

P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848

P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912

P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695

P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431

P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371

P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442

P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062

The unusual X values ​​for this model are: X = 0, 1, 7, 8

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