3 years ago

X+3, -2x^(2)-6x, 4x^(3)+12x^(2) what is the 8th term in this geometric sequence

Mathematics

1 answer:

seraphim [82]3 years ago

4 0

Answer:

a8 = -128x^8 -384x^7

Step-by-step explanation:

The formula for the general term of a geometric sequence with first term a1 and common ratio r is ...

an = a1·r^(n-1)

Here, we have a1 = (x+3) and r = (-2x^2-6x)/(x+3) = -2x. Then the 8th term is ...

a8 = (x+3)(-2x)^(8-1)

a8 = -128x^8 -384x^7

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