Answer: 1) 
2) 55 points
Step-by-step explanation:
1) A= 8w + 18, w=1.25
A = 8(1.25) + 18
A = 10 + 18
A = 28ft^2
2) 25 points to start with, additional 5 points per magazine they sell, m = number of magazines they sell
total points = 25 + 5m
How many if they sell 6?
total = 25 + 5(6)
= 25 + 30
total = 55
The initial height of the balloon is 10 feet which then increases by 70% to (10 ×1.7) = 17 feet, then to (17 × 1.7) =28.9 feet, and so fourth if the rate of increase is kept constant. Therefore, forming a geometric sequence such that to get any term in the sequence we use the formula ar∧(n-1), where a is the first term, r is the common ratio, and n is the term in the sequence. In this case a is 10 and r= 1.7 , to get the height in the fourth minute it means n =5 (for the first term there is 0 minutes, such that for 0 minutes n= 1)
Thus, 10 × 1.7 ∧ 4 = 83.521 feet.
Therefore, the answer is 83.521 feet
1)
A has a greater principal
2)
Principal of A is $500, the principal of B is $400, so A's principal is greater by $100
3)
Annual interest rate of A:
10/500 x 100
interest rate of A = 2%
The interest rate of B is higher.
4)
B's annual interest rate is 5% and A's annual interest rate is 2%, so B's is higher by 3%.
Answer:
Step-by-step explanation:
Check attachment for solution
Answer:
NO amount of hour passed between two consecutive times when the water in the tank is at its maximum height
Step-by-step explanation:
Given the water tank level modelled by the function h(t)=8cos(pi t /7)+11.5. At maximum height, the velocity of the water tank is zero
Velocity is the change in distance with respect to time.
V = {d(h(t)}/dt = -8π/7sin(πt/7)
At maximum height, -8π/7sin(πt/7) = 0
-Sin(πt/7) = 0
sin(πt/7) = 0
Taking the arcsin of both sides
arcsin(sin(πt/7)) = arcsin0
πt/7 = 0
t = 0
This shows that NO hour passed between two consecutive times when the water in the tank is at its maximum height