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nexus9112 [7]
3 years ago
9

Find the range. 3 –9 7 –1 5 –4 2 2 16 8 –1

Mathematics
1 answer:
Schach [20]3 years ago
3 0
The range is the <em>distance between the minimum data value and the maximum</em>: \text{Maximum value}-\text{Minimum value}=\text{Range}

\text{Given values: }3, -9, 7, -1, 5, -4, -2
Your <u>minimum value is -9</u>.
Your <u>maximum value is 7</u>.

Therefore: \text{Range}\rightarrow\text{Maximum value}-\text{Minimum value}\rightarrow7-(-9)
\rightarrow\text{Subtracting Negative Values}\rightarrow7+9=16
<em>
</em><em>**Subtracting a negative value </em>-a <em>is like adding the product</em> (-1)(-a)<em>, which would translate to the same thing as</em><em> adding the product </em><em />(1)(a)<em>, or adding </em>a.
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4 3/10 divided by 3/5
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7.16

Step-by-step explanation:

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The set of x valúes of a function this is another name of range
marin [14]

Answer:

  False?

Step-by-step explanation:

We can't tell what the question is here, but it looks like you want to know about the definition of domain and range.

The set of x-values is the <em>domain</em>.

The set of y-values is the <em>range</em>.

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8 0
3 years ago
Find x<br> a) 21 √2<br> b)7<br> c)21 √2/2<br> d)21 √3/2
fgiga [73]

Answer:

C

Step-by-step explanation:

Use the sine ratio in the left, right triangle to find the common side to both triangles and the exact values

sin60° = \frac{\sqrt{3} }{2} , cos45° = \frac{1}{\sqrt{2} } , thus

sin60° = \frac{opposite}{hypotenuse} = \frac{opp}{7\sqrt{3} } = \frac{\sqrt{3} }{2} ( cross- multiply )

2 × opp = 21 ( divide both sides by 2 )

opp = \frac{21}{2}

Now consider the right triangle on the right, using the cosine ratio

cos45° = \frac{adjacent}{hypotenuse} = \frac{\frac{21}{2} }{x} = \frac{1}{\sqrt{2} } ( cross- multiply )

x = \frac{21}{2} × \sqrt{2} = \frac{21\sqrt{2} }{2} → C

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3 years ago
What is the domain of
Vsevolod [243]
The domain of what??
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4 years ago
Read 2 more answers
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