The equidistant point for all three, will be the "centroid" of their triangular locations
thus
There are 120 different combinations.
There are 5 to use for the first bead; then after it is used, 4 for the second; 3 for the third; 2 for the fourth; and 1 for the fifth and last bead:
5*4*3*2*1 = 120.
Answer:
x=40
Step-by-step explanation:
Answer:

Step-by-step explanation:
We want to find the sum of

We can rewrite this as

This becomes;

Recall that;

This implies that;

Combine like terms:

1. <span>true
example:
2+3=3+2
5=5
2. </span><span>true
</span>example:
3*4=4*3
12=12
<span>
3. false
</span>example:
6-3=3-6
3≠-3
<span>
4. </span><span>true
</span>example:
(4 + 3) + 2= 4 + (3 + 2)
7 + 2 = 4 + 5
9 = 9
<span>
5. false
</span>example:<span>
(9 - 6) - 3 = 9 - (6 - 3)
</span>3 - 3 = 9 - 3
0 ≠ 6
6. true
example:
<span>2(3+4)= 2*3+2*4
2 * 7 = 6 + 8
14 = 14</span>