Answer:
Distance between two points= √(x2-x1)²+(y2-y1)²
D= 15units
Let "k" be the y-coordinate of A
A(-6,k)
B(3,2)
15= √(3--6)²+(2-k)²
Taking square of both sides to eliminate the square root.
15²=(9)²+(2-k)²
225=81+4-4k+k²
k²-4k - 140=0
Using Quadratic Formula to evaluate
k= 14 or k=-10
The Possible coordinates of A are
(-6,14) or (-6,-10)
Answer:
Cos^2x csc^2x
Step-by-step explanation:
Cos^2x (1 + cot^2x)
Answer:
possible answers below!
Step-by-step explanation:
if they are vertical angles then the measure of ZB is 78
if they are supplementary then ZB is 102 degrees
if they are complementary then ZB is 12 degrees
It depends on where its located, cant really help if i dont have a pic..but i hope this helps! :)
69×2 [8+12-10×2+ (7-5) -1] -6
69×2 [8+12-10×2+2-1] -6
69×2 [8+12-20+2-1] -6
69×2 [20-20+2-1] -6
69×2 [0+2-1] -6
69×2 [1] -6]
138 [1] -6
138-6
132
I believe this is ur answer.
