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3 years ago

Solve the system of equations. 72f-12g=96 6f-2g=10

Mathematics

1 answer:

mr Goodwill [35]3 years ago

7 0

Answer:

72f - 12g = 96

-36f +12g = -60

36f = 36

f = 1

6 - 2g = 10

-2g = -16

g = 8

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A health club charges non-members $5 per day to swim and $9 per day for an exercise class. Members pay a yearly fee of $300 plus

Ivahew [28]

The number of days d, he must use the gym to make the membership worthwhile is at least 21 days

Equation

Non members:

Cost of swimming per day = $5

Cost of exercise per day = $9

Total = $5 + $9

= $14

Members:

Yearly fee = $300

Exercise fee per day = $4

Swimming fee = $0

The number of days d, he must use the gym to make the membership worthwhile = $300 ÷ 14

= 21.42857142857142

Approximately,

21 days

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1 year ago

Simplify the following expression completely, where x is greater than or equal too 0.

Dennis_Churaev [7]

First you want the numbers under the radical to be the same so you can combine like terms.

$x \sqrt{5xy^4} =x \sqrt{5x*^4y} = xy^2 \sqrt{5x}$
$\sqrt{405x^3y^4} = \sqrt{5x*81x^2y^4} =9xy^2 \sqrt{5x}$
$\sqrt{80x^3y^4} = \sqrt{5x*16x^2y^4} = 4xy^2 \sqrt{5x}$

Now add together to get $14xy^2 \sqrt{5x}$

7 0

2 years ago

Read 2 more answers

The area of a field shaped like a right triangle is 750yd^2.One leg of the field is fenced with wood costing $5/yd. the remainde

Elenna [48]

Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.

The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)

The perimeter is 150yd, therefore
a + b + c = 150 (2)

Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)

From (2), obtain
c = 150 - a - b (4)

Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60

From (1), obtain
60b = 1500
b = 25

From (4), obtain
c = 150 - 60 - 25 = 65

Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.

5 0

3 years ago

If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!

timama [110]

$x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0$

By the quadratic formula,

$x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2$

Then

$(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2$

$\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}$

Multiply numerator and denominator by the denominator's conjugate:

$\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15$