Answer:
Relations B and E do not represent the function.
Step-by-step explanation:
We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.
In other words, we can not have duplicated inputs as there should be only 1 output for each input.
If we closely observe relation B, and E i.e.
- B) {(3,4), (4,5), (3,6). (6,7)}
Relation 'B' IS NOT A FUNCTION
Relation B has duplicated or repeated inputs i.e. x = 3 appears twice times. we can not have duplicated inputs as there should be only 1 output for each input.
Thus, relation B is NOT a function.
Relation 'E' IS NOT A FUNCTION
Relation E has duplicated or repeated inputs i.e. x = 4 appears twice times. we can not have duplicated inputs as there should be only 1 output for each input.
Thus, relation B is NOT a function.
Therefore, relations B and E do not represent the function.
This is a combination in which you choose 4 from 10.
The formula is
combinations = 10! / 4! * (10-4)!
combinations = 10! / 4! * 6!
combinations = 10 * 9 * 8 * 7 * 6! / 4! * 6!
combinations = 10 * 9 * 8 * 7 / 4 * 3 * 2
combinations = 10 * 3 * 7
combinations = 210
Source:
http://www.1728.org/combinat.htm
15%=3
5%=1
5(20)=100
1(20)=20
So, there are 20 students in the class.
Answer:
5,500
Step-by-step explanation:
this is quite simple
multiply his earnings by a tenth
55,000 times 1/10
5,500
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