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AlekseyPX
3 years ago
14

Which describes the median set of data

Mathematics
1 answer:
blagie [28]3 years ago
3 0

In a set of data, to find the median you first have to order your data from greatest to least then find the center or (median) of your data. E is your answer.

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What value for C will make the expression a perfect square trinomial x2-7x+c
Tom [10]

Answer:

The value of c is 12.25

Step-by-step explanation:

we know that

A perfect square trinomial is of the form

(x-a)^{2}=x^{2}-2ax+a^{2}

In this problem we have

x^{2}-7x+c

so

equate the equations

x^{2}-7x+c=x^{2}-2ax+a^{2}

we have

the following equations

-7x=-2ax -----> equation A

and

c=a^{2} -----> equation B

<u>Solve the equation A</u>

-7x=-2ax

7=2a

a=3.5

<u>Solve the equation B</u>

c=a^{2}

c=3.5^{2}=12.25

therefore

(x-3.5)^{2}=x^{2}-7x+12.25

The value of c is 12.25

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Step-by-step explanation:

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Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably norma
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Answer:

The degrees of freedom is 11.

The proportion in a t-distribution less than -1.4 is 0.095.

Step-by-step explanation:

The complete question is:

Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4  if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion

Solution:

The information provided is:

n_{1}=n_{2}=12\\t-stat=-1.4

Compute the degrees of freedom as follows:

\text{df}=\text{Min}.(n_{1}-1,\ n_{2}-1)

   =\text{Min}.(12-1,\ 12-1)\\\\=\text{Min}.(11,\ 11)\\\\=11

Thus, the degrees of freedom is 11.

Compute the proportion in a t-distribution less than -1.4 as follows:

P(t_{df}

                      =P(t_{11}>1.4)\\\\=0.095

*Use a <em>t</em>-table.

Thus, the proportion in a t-distribution less than -1.4 is 0.095.

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