A linear relation is a relationship between two variables that when the corresponding pair of values of the variables are plotted, a straight line is obtained

The equation for the relationship between hours Gwen worked and number of tickets is t = 15·h

The reason the above equation is correct is as follows:

The given parameters are;

The table of values;

Hours(h): 1, 2, 3, 4

Tickets (t): 15, 30, 45, 60

Required: To write an equation that gives the relation between the number of hours Gwen worked and the number of tickets sold

Solution:

From the given table, we have;

The common difference between successive h-values is 1

The common difference between successive t-values is 30 - 15 = 45 - 30 = 60 - 45 = 15 = Constant

Given that the common difference of the h, and t-values are constant, the relationship is a linear relationship of the form, t = m·h + c

Where;

m = The rate of change of t with h, as follows;

m = (30 - 15)/(2 - 1) = 15

∴ t - 15 = 15 × (h - 1)

t - 15 = 15·h - 15

t = 15·h - 15 + 15 = 15·h

t = 15·h

The equation for the relation between the number of hours Gwen worked and the number of tickets she sold is t = 15·h

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7 0

3 years ago

(05.02)

Damm [24]

Answer:

40 Degrees

Step-by-step explanation:

A triangle has a total of 180 degrees therefore if you add up the angles and then subtract by 180 you would get 40 degrees.

4 0

3 years ago

6 1/6 6 1/3 6 2/3 6 3/2

Vladimir [108]

Given:

The expression is

$\sqrt{\sqrt[3]{6}}$

To find:

The simplified form of the given expression.

Solution:

We have,

$\sqrt{\sqrt[3]{6}}$

Using the properties of radical and exponent, we get

$=(\sqrt[3]{6})^{\frac{1}{2}}$ $[\because \sqrt{x}=x^{\frac{1}{2}}]$

$=\left(6^{\frac{1}{3}}\right)^{\frac{1}{2}}$ $[\because \sqrt[n]{x}=x^{\frac{1}{n}}]$

$=6^{\frac{1}{3}\times\frac{1}{2}}$ $[\because (a^m)^n=a^{mn}]$

$=6^{\frac{1}{6}}$

Therefore, the correct option is A.

8 0

3 years ago

Calculate s5 for the sequence defined by

pantera1 [17]

ANSWER

$S_5= 42.5$

EXPLANATION

The general term of the arithmetic sequence is

$a_n=1+\frac{5}{2}n$

For the first term,we substitute $n=1$ to get,

$a_1=1+\frac{5}{2}\times 1$

$a_1=1+2.5=3.5$

Similarly

$a_5=1+\frac{5}{2}\times 5$

$a_5=13.5$

The sum of the first n-terms is given by the formula,

$S_n=\frac{n}{2}(a_1+l)$

where l is the last term.
In this case

$l=a_5=13.5$

We substitute these values to get,

$S_5= \frac{5}{2} (3.5 + 13.5)$

$S_5= \frac{5}{2} (17)$
$S_5=42.5$

We could have also used the formula,

$S_n=\frac{n}{2}(2a_1+(n-1)d)$

$S_5=\frac{5}{2}(2(3.5)+(5-1)2.5)$

$S_5=42.5$

3 0

4 years ago

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