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Lynna [10]
4 years ago
11

What is the formula and measure of each of these?

Physics
1 answer:
Bingel [31]4 years ago
8 0

the symbol of mass is similar to meter but actually it is different,ve careful

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is acting on an object that is constrained to move along the x-axis. If the force moves the object 3m, from the origin, what is
Snezhnost [94]

Answer:

U = - ∫ F dx

U = - 3F₀

Explanation:

Force and potential energy are related

         F = - \frac{dU}{dx}

         dU = - F dx

        ∫ dU = - ∫ F dx

        U- U₀ = - ∫ F dx

to solve the problem we must know the form of the force, if we assume that F = F₀ and U₀ = 0 for x = 0

         U = - F₀ 3

8 0
3 years ago
A projectile is fired at an angle above the level ground. Where does it have maximum kinetic energy? Is it right when it leaves
Lorico [155]
You can approach this problem in an analytical way. The formula for kinetic energy is 1/2*mv². Throughout the projectile motion, mass is constant. Therefore, it wholly depends on the velocity.<em> So, the maximum kinetic energy is when the object travels the fastest. This is right when it leaves the launcher, and the moment just before it hits the ground.</em>
5 0
3 years ago
Read 2 more answers
I will mark you brainlist please help
denis-greek [22]

Answer:15th

Explanation:

I believe it will fall on the 15th stair because 10 times 15 is 150 divided by 10 m/s equals 15

8 0
3 years ago
Help
lakkis [162]
Set up a unit conversion problem, arrange units to convert minutes to seconds, then cancel all time units.

8.3 minutes x (60 seconds/1 minute) x ( 3.00x10^8 meters/1 second) = 149,400,000,000 meters

Since the time is the term with the fewest number of significant figures (2), your answer should only be expressed with two sig figs as well.

1.5x10^11 m
7 0
3 years ago
In the figure, if Q = 52 µC q =10 µC and d = 55 cm, what is the magnitude of the electrostatic force on q?​
GenaCL600 [577]

Answer:

F = 15.47 N

Explanation:

Given that,

Q = 52 µC

q = 10 µC

d = 55 cm = 0.55 m

We need to find the magnitude of the electrostatic force on q. The formula for the electrostatic force is given by :

F=k\dfrac{q_1q_2}{d^2}\\\\F=9\times 10^9\times \dfrac{52\times 10^{-6}\times 10\times 10^{-6}}{(0.55)^2}\\\\F=15.47\ N

So, the magnitude of the electrostatic force is 15.47 N.

4 0
3 years ago
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