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NikAS [45]
3 years ago
5

HELP || A delivery van has a mass of 7000 kg and a kinetic energy of 31,500 J. What is the speed? A) 4.5 m/s B) 2.1 m/s C) 3 m/s

D) 9 m/s

Physics
2 answers:
Trava [24]3 years ago
4 0

Answer:

the speed is 3m/s

Explanation:

below is the working

barxatty [35]3 years ago
3 0

Answer:

A - 4.5 m/s

Explanation:

31,500/7,000= 4.5

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A long, thin straight wire with linear charge density ? runs down the center of a thin, hollow metal cylinder of radius R. The c
MaRussiya [10]

Answer:

a. E = \frac{\lambda }{(2\epsilon * r) }

b. E = \frac{3(lambda)}{2\pi*\epsilon(outside)  }

Explanation:

The important thing to remember is to use Gauss Law. This is a relation that describes the distribution of electric charge to the resultant electric field.

Linear charge density means charge per unit length of material.

Data:

The metal cylinder is hollow.

The unit length is L.

a.The expression will be as follows:

for charge inside the cylinder, where r < R, the expression is:

E = \frac{\lambda }{(2\epsilon * r) }

b. Let's assume that the cylinder is a coaxial cylinder with a radius r > R, then the electrical field strength is given as:

E = \frac{Q ( enclosed)}{A*\epsilon }

E = \frac{\lambda*L+2(\lambda)*L }{(A)*\epsilon(outside) }

E  = \frac{3(\lambda)L }{(2\pi*R*L*\epsilon(outside)  }

This gives:

E = \frac{3(lambda)}{2\pi*\epsilon(outside)  }

The solution informs us that there is a surface change taking place on the cylinder. Therefore, there will not be a magnetic field across it.

3 0
4 years ago
If velocity is 0.2m/s, what is the kinetic energy?
Natalija [7]

\huge\boxed{♧ \: \mathfrak{ \underline{Answer} \: ♧}}

we know,

\boxed{kinetic  \:  \: energy =  \frac{1}{2} m {v}^{2} }

So,

\longmapsto \dfrac{1}{2}  \times 10 \times 0.2 \times 0.2

\longmapsto0.2 \: joules

3 0
3 years ago
2 Resistors of resistance, R = (100 +- 3) Ohm, R2 = (200+-4)Ohm are connected in Parallel and Series.
Orlov [11]

According to what I've learnt, in any expression of multiplication or division, the percentage errors of each term are added up to find the equivalent percentage error. That is, if

<span><span>y=<span>ABC
</span></span><span>
y=<span>ABC</span></span></span>then<span><span>% error in y= % error in A + % error in B + % error in C</span></span>

For the above problem, let <span><span>Rs</span></span> denote series combination. Then <span><span><span>Rs</span>=300±7</span></span> ohm.

Let <span><span>Rp</span></span> denote parallel combination.

<span><span>∴<span>Rp</span>=<span><span><span>R1</span><span>R2/</span></span><span><span>R1</span>+<span>R2 </span></span></span>= <span><span><span>R1</span><span>R2/</span></span><span>Rs</span></span></span></span>

Ignoring errors, we get <span><span><span>Rp</span>=<span>200/3 = </span></span></span><span><span>66.67</span></span> ohm

<span><span>%<span>error in R1</span>=3</span></span>, <span><span>%<span>error in R2</span>=2</span></span>, <span><span>%<span>error in Rs</span>=<span>7/3</span></span></span>

Hence, <span><span>%<span>error in Rp</span>=3+2+<span>7/3</span>=<span>22/3</span></span></span>

So, error in <span><span>Rp</span></span> will be <span><span><span>22/3</span>% of </span></span><span><span>200/3</span></span>, which is approximately <span>4.89.</span>

Hence, I got <span><span><span>Rp</span>=66.67±4.89</span></span> ohm.

However, the book used the formula described and proved here and arrived at the answer <span><span><span>Rp</span>=66.67±1.8</span></span>ohm.

8 0
3 years ago
Read 2 more answers
What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 1.200 kg of the substance increases i
Anarel [89]

Answer:

0.035 J/g°C

Explanation:

From the question given above, the following data were obtained:

Heat (Q) absorbed = 2500 J

Mass (M) = 1.2 Kg

Initial Temperature (T₁) = 10 °C

Final Temperature (T₂) = 70 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial Temperature (T₁) = 10 °C

Final Temperature (T₂) = 70 °C

Change in temperature (ΔT) =

ΔT = T₂ – T₁

ΔT = 70 – 10

ΔT = 60 °C

Thus, the change in the temperature of the substance is 60 °C

Next, we shall convert 1.2 Kg to grams (g). This can be obtained as follow:

1 Kg = 1000 g

Therefore,

1.2 Kg = 1.2 Kg × 1000 g / 1 Kg

1.2 Kg = 1200 g

Thus, 1.2 Kg is equivalent to 1200 g.

Finally, we shall determine the specific heat capacity of substance. This can be obtained as follow:

Heat (Q) absorbed = 2500 J

Mass (M) = 1200 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) =?

Q = MCΔT

2500 = 1200 × C × 60

2500 = 72000 × C

Divide both side by 72000

C = 2500 / 72000

C = 0.035 J/g°C

Therefore, the specific heat capacity of the substance is 0.035 J/g°C

3 0
3 years ago
33] You have long hair, you should:
Sveta_85 [38]

Answer:

B

Explanation:

hair can be a safety hazard

4 0
3 years ago
Read 2 more answers
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