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Anna [14]
3 years ago
6

Find the values of a, b and c in the equation below (x^5yz^4)^3/x^3yz= x^a y^b z^c

Mathematics
1 answer:
alex41 [277]3 years ago
7 0

Answer: a = 12, b = 2, c = 11

Step-by-step explanation:

Using exponent rules we can distribute the exponent of 3 to the xyz.

This results in the numerator now being. x^{5*3}+y^{1*3}+z^{4*3}\\ This can be simplified to, x^{15}y^{3}z^{12}\\.

Now divide the numerator by the denominator subtracting the exponents.

Which equals, x^{12}y^{2}z^{11}

So a = 12

b = 2

and

c = 11

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Mrs. Fowler has 28 students in her class, and 16 of them are boys.
Elan Coil [88]
We subtract 28 - 16 and get the number of girls 
so lets do that 
28 - 16 = 12 
now we know the unsimplified ratio os 12 to 16 
simplifed girls 12 ÷ 4 = 3 
simplified boys 16 ÷ 4 = 4 
since it says (girls to boys) we put girls first then boys
so it would become 3 : 4 
Or the answer is B.) 3 : 4 
5 0
3 years ago
Michael wants to rent a boat and spend less than $53 the boat cost six dollars per Michael wants to rent a boat and spend less t
ASHA 777 [7]
Hi hope I helped, ok so first 6×7=42 and its less than 53 so ur answer is 42
5 0
3 years ago
Given: cos θ=-4/5, sin x = -12/13, θ is in the third quadrant, 
USPshnik [31]

By definition of tangent,

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

Recall the double angle identities:

sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)

cos(2<em>θ</em>) = cos²(<em>θ</em>) - sin²(<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

where the latter equality follows from the Pythagorean identity, cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1. From this identity we can solve for the unknown value of sin(<em>θ</em>):

sin(<em>θ</em>) = ± √(1 - cos²(<em>θ</em>))

and the sign of sin(<em>θ</em>) is determined by the quadrant in which the angle terminates.

<em />

We're given that <em>θ</em> belongs to the third quadrant, for which both sin(<em>θ</em>) and cos(<em>θ</em>) are negative. So if cos(<em>θ</em>) = -4/5, we get

sin(<em>θ</em>) = - √(1 - (-4/5)²) = -3/5

Then

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

tan(2<em>θ</em>) = (2 sin(<em>θ</em>) cos(<em>θ</em>)) / (2 cos²(<em>θ</em>) - 1)

tan(2<em>θ</em>) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

tan(2<em>θ</em>) = 24/7

4 0
3 years ago
The base of a 15-foot ladder is 6 feet from a building. If the ladder reaches the flat roof, how tall is the building?
Vlad [161]

Answer:

the answer would be 13.75 feet

Step-by-step explanation:

The computation of the tall is the building as follows:

Given that

Base is 6 foot

And, the hypotheses is 15 feet

Here we use the Pythagoras theorem

= √15^2 - √6^2

= √225 - √36

= √189

= 13.75 feet

Hence the answer would be 13.75 feet

6 0
3 years ago
How many solutions does the equation have? -3f + 3f = 0
Ulleksa [173]

Answer:

infinite solutions

Step-by-step explanation:

-3f + 3f = 0

0=0

This is always true so there are infinite solutions

7 0
3 years ago
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