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3 years ago

Help!! Please Im failing on math!!!

Mathematics

2 answers:

Ad libitum [116K]3 years ago

6 0

Answer:

can you add the question........

Step-by-step explanation:

Amiraneli [1.4K]3 years ago

3 0

We’re is the question

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33 points!! The line contains the point (4,-2) and is perpendicular to 4x+3y=-6 The equation of the line is:

Deffense [45]

Answer:

y = 3/4 x - 5

Step-by-step explanation:

The slopes of perpendicular lines are negative reciprocals. We find the slope of the given line. Then we can find the slope of the reciprocal.

4x + 3y = -6

Solve for y.

3y = -4x - 6

y = -4/3 x - 2

The slope of the original line is -4/3.

The slope of the perpendicular is 3/4.

Now we need to find the equation of line with slope 3/4 that contains point (4, -2).

y = mx + b

-2 = (3/4)(4) + b

-2 = 3 + b

-5 = b

b = -5

The equation is

y = 3/4 x - 5

5 0

3 years ago

Which expression is equivalent to 8a + 20?

Darina [25.2K]

To determine the expression that is equivalent to 8a + 20, all you have to do is find the common denominator and divide the values by it.

8a + 20
8a/4 + 20/4
4(2a + 5).

The correct solution would cue the second option - 4(2a + 5).

3 0

4 years ago

Read 2 more answers

Given f(x)=x2+2x−8, find f(−2).

Sloan [31]

Answer:

-8 is the answers for the question

Step-by-step explanation:

please please give me brainlest

6 0

3 years ago

Read 2 more answers

The line $y = 3$ intersects the graph of $y = 4x^2 + x - 1$ at the points $A$ and $B$. The distance between $A$ and $B$ can be w

raketka [301]

Answer:

Step-by-step explanation:

Let's find the points $A$ and $B$ .

We know that the $y$ -coordinates of both are $3$ .

So let's first solve:

$3=4x^2+x-1$

Subtract 3 on both sides:

$0=4x^2+x-1-3$

Simplify:

$0=4x^2+x-4$

I'm going to use the quadratic formula, $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , to solve.

We must first compare to the quadratic equation, $ax^2+bx+c=0$ .

$a=4$

$b=1$

$c=-4$

$\frac{-1 \pm \sqrt{1^2-4(4)(-4)}}{2(4)}$

$\frac{-1 \pm \sqrt{1+64}}{8}$

$\frac{-1 \pm \sqrt{65}}{8}$

Since the distance between the points $A$ and $B$ is horizontal. We know this because they share the same $y-coordinate$ .This means we just need to find the positive difference between the $x$ -values we found for the points of $A$ and $B$ .