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Mnenie [13.5K]
3 years ago
11

An event that is made up of two or more outcomes is called.....

Mathematics
1 answer:
kupik [55]3 years ago
7 0
An event that is made up of two or more outcomes is called a compound event.
Hope this helps!
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What transformations change the graph of f(x) to the graph of g(x)?
Dennis_Churaev [7]

For this case we have that the main function is given by:

f (x) = - 7x ^ 2

We apply the following transformations:

Vertical expansions:

To graph y = a * f (x)

If a> 1, the graph of y = f (x) is expanded vertically by a factor a.

For a = 5 we have:

h (x) = 5 * f (x)\\h (x) = 5 * (- 7x ^ 2)\\h (x) = - 35x ^ 2

Vertical translations:

Suppose that k> 0

To graph y = f (x) + k, move the graph of k units up.

For k = 5 we have:

g (x) = h (x) + k\\g (x) = - 35x ^ 2 + 5

Answer:

The graph of g (x) is the graph of f (x) stretched vertically by a factor of 5 and translated up 5 units.

3 0
3 years ago
Read 2 more answers
Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m
Molodets [167]

Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1).

The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

8 0
3 years ago
Convert: 2 meters to centimeters
Mashcka [7]
2 meters = 200 centimeters
7 0
3 years ago
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A jog runs at a speed of 4m/s for 10 minutes. Work out the distance travelled.
krok68 [10]

Answer:

2,400 meters

Step-by-step explanation:

4 × 60 sec = 240 meters a minutes

240 meters × 10 minutes = 2,400 meters in 10 minutes

7 0
3 years ago
Solve the system of equations given below
Fantom [35]

y-15=3x \\-2x+5y=-3 \\ \\-2x+y-15=0 /\cdot2 \\-2x+5y-3=0 /\cdot(-2) \\ \\-4x+2y-30=0 \\4x-10y+6=0 \\ \\-8y-24=0 \\\boxed{y=-3} \\ \\-3-15=3x \\\boxed{x=-6}

The answer is C. (-6, -3)

Hope this helps.

r3t40

8 0
3 years ago
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