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victus00 [196]
3 years ago
6

Solve the equation for n. 5 = -4 + 27/n

Mathematics
2 answers:
Usimov [2.4K]3 years ago
7 0

Answer:

n=3

Step-by-step explanation:

Bond [772]3 years ago
4 0
The answer to that question is N=3.
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9.54
damaskus [11]

Answer:

9.5

Step-by-step explanation:

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3 years ago
Find x.<br> the answer can be in a integer or it could be in a decimal it doesn’t really matter.
Svetllana [295]

Answer:   42

Step-by-step explanation:  Subtract 81 from 123                 ;) your welcome

8 0
3 years ago
The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum? ​
VLD [36.1K]

Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that

<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>

<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>

where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.

Then the sum is

<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>

and its magnitude is

||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

5 0
3 years ago
Read 2 more answers
In AABC, the measure of ZC=90°, the measure of ZA=63°, and AB = 35 feet. Find the
irinina [24]

Answer:

40 feet

Step-by-step explanation:

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8 0
3 years ago
X/2+3= 5 its solving equations (with three terms) please help me
olganol [36]
Multiply each side by 2: 2(x/2) + 3(2) = 5(2) => x + 6 = 10

Subtract 6 from each side: x + (6 - 6) = 10 - 6 => x = 4

The answer is x is equal to 4.
8 0
3 years ago
Read 2 more answers
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