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Helen [10]
4 years ago
12

Write an equation of the line containing the given point and perpendicular to the given line:

Mathematics
1 answer:
bazaltina [42]4 years ago
4 0

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line is

2x+9y=5

9y = - 2x + 5

y = -2x/9 + 5/9

Comparing with the slope intercept form, slope = -2/9

If the line passing through the given point is perpendicular to the given line, it means its slope is the negative reciprocal of the slope of the given line.

Therefore, the slope of the line passing through (4,-9) is 9/2

To determine the intercept, we would substitute m = 9/2, x = 4 and y = -9 into y = mx + c. It becomes

- 9 = 9/2×4 + c = 18 + c

c = - 9 - 18 = - 27

The equation becomes

y = 9x/2 - 27

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Given the directrix of y = 6 and focus of (0, 4), which is the equation of the parabola?
krok68 [10]

y = \frac{1}{24} x^{2}

<u>Step-by-step explanation:</u>

Since directrix is a horizontal line, this is a regular vertical parabola, where the x part is squared.  The equation of a vertical parabola is:

(x - h)² = 4p(y - k)    

where,

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So, we need to find out h, k and p and plug those values :

We know that the vertex of a parabola is halfway between focus and the directrix . We know the focus (0,4) and directrix y = 6  therefore, vertex (h,k) = (0, 0)

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= distance from the (0,0) to the (0,4)

= 4

Plug all the values in equation:

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Now, we rearrange to write this into standard form (y =ax^{2}+bx+c)

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Find the 16th term of the arithmetic sequence whose common difference is d=6 and whose first term is a1=1.
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Answer:

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Step-by-step explanation:

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