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kozerog [31]
3 years ago
13

Normal six-sided dice have a different number of pips on each face, from 1 to 6. You roll two such dice and add the result.

Mathematics
1 answer:
NARA [144]3 years ago
6 0

Answer:

1) 16.7% probability of rolling 10+.

2) 50% probability an odd number is rolled.

3) 7 is the most likely total result.

Step-by-step explanation:

These are all the possible outcomes:

(1,1), (1,2), (1,3), (1,4), (1,5),(1,6)

(2,1), (2,2), (2,3), (2,4), (2,5),(2,6)

(3,1), (3,2), (3,3), (3,4), (3,5),(3,6)

(4,1), (4,2), (4,3), (4,4), (4,5),(4,6)

(5,1), (5,2), (5,3), (5,4), (5,5),(5,6)

(6,1), (6,2), (6,3), (6,4), (6,5),(6,6)

There are 36 possible outcomes

1) what is the probability of rolling 10+?

There are 6 possible outcomes in which 10+ is rolled:

(4,6), (5,5),(5,6), (6,4), (6,5),(6,6).

So there is a 6/36 = 0.167 = 16.7% probability of rolling 10+.

2) what is the probability of rolling an odd number?

There are 18 possible outcomes in which an odd number is rolled.

So there is a 18/36 = 0.5 = 50% probability an odd number is rolled.

3) what is the total that is most likely to result?

There are 6 outcomes in which 7 is rolled.

So 7 is the most likely total result.

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nata0808 [166]
4a + 2b = 10

you are solving for b

isolate the b

subtract 4a from both sides

4a (-4a) + 2b = 10 (-4a)

2b = 10 - 4a

divide 2 from both sides to isolate the b

2b(/2) = (10 - 4a)/2

b = (10 - 4a)/2

b = 5 - 2a

C) b = -2a + 5 is your answer

hope this helps
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