1.00 would be your answer because 95 rounded up is 100. So, 0.95 is closest to 1.00
Answer:
Step-by-step explanation:
The height of the marshmallow (in feet) is represented by the equation h=−16t2+8t+48,
where t is the time (in seconds) after he throws the marshmallow.
The equation is a quadratic equation. When the marshmallow hits the ground, its height from the ground will be zero. Therefore
−16t^2+8t+48 = 0
- 2t^2 + t + 6 = 0
Multiplying through by the negative sign. It becomes
2t^2 - t - 6 = 0
2t^2 + 3t - 4t - 6 = 0
t(2t + 3) - 2(2t + 3) = 0
(t - 2)(2t + 3) = 0
t - 2 = 0 or 2t + 3 = 0
t = 2 or t = - 3/2
The time cannot be negative
So it will take 2 seconds to hit the ground
Answer:
5x^2
Step-by-step explanation:
12 can be taken out from the top and bottom then for the x you subtract
You should use a T distribution to find the critical T value based on the level of confidence. The confidence level is often given to you directly. If not, then look for the significance level alpha and compute C = 1-alpha to get the confidence level. For instance, alpha = 0.05 means C = 1-0.05 = 0.95 = 95% confidence
Use either a table or a calculator to find the critical T value. When you find the critical value, assign it to the variable t.
Next, you'll compute the differences of each pair of values. Form a new column to keep everything organized. Sum everything in this new column to get the sum of the differences, which then you'll divide that by the sample size n to get the mean of the differences. Call this dbar (combination of d and xbar)
After that, you'll need the standard deviation of the differences. I recommend using a calculator to quickly find this. A spreadsheet program is also handy as well. Let sd be the standard deviation of the differences
The confidence interval is in the form (L, U)
L = lower bound
L = dbar - t*sd/sqrt(n)
U = upper bound
U = dbar + t*sd/sqrt(n)
