Question

How do I do it when it’s a different base ?

Answer 1

Answer:

$x=-2$

Step-by-step explanation:

You gotta use natural log, ln().

Taking the ln() of a number will bring down its exponent:

Example:

If given $x^k$

then $ln(x^k)=k\cdot ln(x)$

In your problem, we have...

$2^{2x+4}=1$

$ln(2^{(2x+4)})= ln(1)$

$(2x+4)ln(2)= ln(1)$   ,  ln(1)=0 always. memorize this value

$(2x+4)ln(2)= 0$         , divide both side by ln(2)

$(2x+4)= 0$

$2x= -4$

$x=-2$