Question

Quadratic formula to find the zeros b^2-4b+4=0

Answer 1

Answer:

Step-by-step explanation:

Remark

I don't think you need the quadratic formula for this equation. It just factors into (b - 2)(b - 2), but I'll do it because you requested it.

Formula

$\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}$

Givens

a = 1

b = - 4

c = 4

Solution

x = - - 4 +/- sqrt((-4^2) - 4*1*4)

       ====================

                   2*1

x = 4 +/- sqrt (16 - 16)

          ==========

              2

x = 4/2

x = 2

There are 2 roots but both of them are the same. Some teachers say there is only 1 root. I'm in that group.