Quadratic formula to find the zeros b^2-4b+4=0

Mathematics

1 answer:

Lunna [17]2 years ago

5 0

Answer:

Step-by-step explanation:

Remark

I don't think you need the quadratic formula for this equation. It just factors into (b - 2)(b - 2), but I'll do it because you requested it.

Formula

$\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}$

Givens

a = 1

b = - 4

c = 4

Solution

x = - - 4 +/- sqrt((-4^2) - 4*1*4)

====================

2*1

x = 4 +/- sqrt (16 - 16)

==========

x = 4/2

x = 2

There are 2 roots but both of them are the same. Some teachers say there is only 1 root. I'm in that group.

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Q # 1 Graph the function Y = |X + 2| - 3

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$\left | x \right |= \left \{ {{x \ \ \ \ x \geq 0} \atop {-x \ \ \ \ x\ \textless \ 0}} \right.$

This is called the Parent Function of the Absolute Value Function.

From the equation:

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The term:

$\left | x+2 \right |$

means that the the Parent Function is shifted two units to the left.

On the other hand, the term:

$-3$

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