Quadratic formula to find the zeros b^2-4b+4=0
1 answer:
Answer:
Step-by-step explanation:
Remark
I don't think you need the quadratic formula for this equation. It just factors into (b - 2)(b - 2), but I'll do it because you requested it.
Formula
Givens
a = 1
b = - 4
c = 4
Solution
x = - - 4 +/- sqrt((-4^2) - 4*1*4)
====================
2*1
x = 4 +/- sqrt (16 - 16)
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2
x = 4/2
x = 2
There are 2 roots but both of them are the same. Some teachers say there is only 1 root. I'm in that group.
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Answer:
Factoring the trinomial: we get the factors
Step-by-step explanation:
We need to factor the trinomial:
We can factor the trinomial by breaking the middle term i.e 13x
Such that adding or subtracting gets the both terms we get 13x and multiplying both terms we get 12x^2
We can break 13x as: 12x and x
Adding them we get 13x and multiplying them we get 12x^2
So,
So, Factoring the trinomial: we get the factors
The pair of equations that has (0, 8) as its solution is: A. equation A and equation C.
<h3>What is the Solution to a System of equations?</h3>The solution to a system of linear equations that are graphed is the pair of x and y coordinates of the points where two lines intersect.
In the graph given, the lines representing equations A and C intersect at point (0, 8). Therefore, the pair of equation that has a solution of (0, 8) is: A. equation A and equation C.
Learn more about solution of a system of equations on:
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