Quadratic formula to find the zeros b^2-4b+4=0
1 answer:
Answer:
Step-by-step explanation:
Remark
I don't think you need the quadratic formula for this equation. It just factors into (b - 2)(b - 2), but I'll do it because you requested it.
Formula
Givens
a = 1
b = - 4
c = 4
Solution
x = - - 4 +/- sqrt((-4^2) - 4*1*4)
====================
2*1
x = 4 +/- sqrt (16 - 16)
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2
x = 4/2
x = 2
There are 2 roots but both of them are the same. Some teachers say there is only 1 root. I'm in that group.
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Our discriminant is 0 so, has one real root.
Option C is correct.
Step-by-step explanation:
we need to find the discriminant and the number of real roots for the following equation:
The discriminant is found by using square root part of quadratic formula:
where b =12, a=4 and c=9
Putting values:
To find out the number of real roots using discriminant we have following rules:
- if discriminant b^2-4ac >0 then 2 real roots
- if discriminant b^2-4ac =0 then 1 real root
- if discriminant b^2-4ac <0 then no real roots
Since our discriminant b^2-4ac is 0 so, has one real root.
Option C is correct.
Keywords: discriminant
Learn more about discriminant at:
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