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mr_godi [17]
3 years ago
7

Miss Levans gave her class an exam on which the possible scores were integers from 0 to 100. If the class median was 91 points a

nd the average was 95 points, what was the top score in the class?
Mathematics
1 answer:
Fudgin [204]3 years ago
8 0

Answer:

  100

Step-by-step explanation:

Suppose there are 2n+1 students in the class. If n+1 of them score 91, and n of them score the high score h, for the average to be 95, we must have ...

  91(n+1) +nh = 95(2n+1)

  91n +91 +nh = 190n +95

  nh = 99n +4

  h = 99 +4/n

The high score must be greater than 99. The high score must be 100.

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Help me Please....................
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9514 1404 393

Answer:

  1.3363

Step-by-step explanation:

The basic idea here is to find an expression for the direction vector between a point on L1 and a point on L2. Then, solve for the points on L1 and L2 that make that vector perpendicular to both lines L1 and L2. (The dot product of direction vectors is zero.) The distance between the points found is the shortest distance between the lines.

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Let P be a point on L1. Then the parametric equation for P is ...

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Let Q be a point on L2. The direction vector for L2 is given by the difference between the given points. It is (4-1, 1-(-1), 6-1) = (3, 2, 5). Then the parametric equation for Q is ...

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The dot product of this and the two lines' direction vectors will be zero:

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The solution to these equations is ...

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  |PQ| = √(94² +1551² +564²)/1237 ≈ 1.3363

The distance between the two lines is about 1.3363 units.

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