Suppose a cube is given. How many different triangles can be formed by connecting 3 of the vertices of the cube?
1 answer:
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- Slope-Intercept Form: y = mx + b, with m = slope and b = y-intercept.
If two lines are perpendicular, then they will have slopes that are <u>negative reciprocals</u> to each other. An example of negative reciprocals are 2 and -1/2
<h2>6.</h2>Now with line 2, I have to convert it to slope intercept form. Firstly, subtract 2x on both sides of the equation:
Next, divide both sides by -5 and your slope-intercept form is
Now since 2/5 is <em>not</em> the negative reciprocal of -2/5, <u>these lines are not perpendicular.</u>
<h2>7.</h2>It's pretty much the same process; convert to slope-intercept and determine if negative reciprocal. This time I'll brush through them:
Now since 2 <em>is</em> the negative reciprocal of -1/2, <u>these lines are perpendicular.</u>
Answer:
Answers in Explanation
Step-by-step explanation:
First Question:
+ [18 ÷ 3 x 4 - 15] - (60 - 7^2 - 1)
+ [24 - 15] - (60 - 49 - 1)
+ 9 - 10
10 + 9 - 10
<u>Answer = 9</u>
Second Question:
5x + 2x = 7x
5x^2 + 3x^2 = 8x^2
2x + 3x - x = 4x
2x + 3y + x + y = 3x + 4y
9x - 6x = 3x
-7y + 3x + 4x + 3y = 7x - 4y
-7x^2 + 2x^2 + 9x^2 = 8x^2
(3x^2 + 5x + 4) - (-1 + x^2) = 2x^2 + 5x + 5
(3 + 2x - x^2) + (x^2 + 8x + 5) = 10x + 8
(3x - 4) - (5x + 2) = -2x - 6
(2x^2 + 5x + 3) - (x^2 - 2x + 3) = x^2 + 7x
(3x^2 + 2x - 5) - (2x^2 - x - 4) = x^2 + 3x - 1
Third Question:
17x + 2y
(5x + 12y) + (3x + y) = 8x + 13y
17x - 8x = 9x
2y - 13y = -11y
Answer: 9x - 11y