Give me some info one what Jenny and Jeremy did and I can help you solve this :)
This problem can be seen as a rectangle triangle where the vertices are:
Vertice 1: home plate
Vertice 2: First base
Vertice 3: second base.
Right angle between vertice 1 and 2 and vertice 2 and 3.
Distance between each base in 90 '.
Calculating then the distance between home plate and second base we have:
d = root ((90) ^ 2 + (90) ^ 2)
d = 127.28 feets
answer:
the distance between home plate and second base is 127.28 feets
Answer:
6/7
Step-by-step explanation:
-3 - 4 -7 -7
---------- = -------- = ------
5 - (-1) 5 + 1 6
Do the inverse of -7/6: 6/7
P = 2(L + W)
P = 44
L = W + 2
44 = 2(W + 2 + W)
44 = 2(2W + 2)
44 = 4W + 4
44 - 4 = 4W
40 = 4W
40/4 = W
10 = W
L = W + 2
L = 10 + 2
L = 12
A = L * W
L = 12
W = 10
A = 12 * 10
A = 120 square inches <===
Any linear equation can be written as
y = mx+b
where m is the slope and b is the y intercept
m = 1/2 in this case. It represents the idea that the snow fell at a rate of 1/2 inch per hour. In other words, the snow level went up 1/2 an inch each time an hour passed by.
b = 8 is the y intercept. It's the starting amount of snow. We start off with 8 inches of snow already.
The info "snow fell for 9 hours" doesn't appear to be relevant here.
