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3 years ago

Solve 20x + 5y = 15 for y

Mathematics

1 answer:

luda_lava [24]3 years ago

7 0

Answer:

Step-by-step explanation:

20x+5y=15

Subtract 20x from both sides.

5y=15−20x

Divide both sides by 5.

__5y_ = _15-20x_____

5 5

y= __15-20______

Divide 15−20x by 5.

y=3−4x

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Answer:

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3 years ago

U guys are mean and never answer my questions, like i paid for no one to answer my question

Sav [38]

Answer:

Step-by-step explanation:

You have no grounds for making a statement like that. There are a variety of reasons why you might not get immediate answers. Be patient.

I will do the second part of this question (finding the first three numbers):

a(4) = a(3)*(-3) + 2 = -148, so a(3)*(-3) = -150 and a(3) = -50

a(3) = 50

a(2) = a(3)*(-3) + 2 = 50, so -3*a(3) = 48 and a(d) = -16

a(1) = a(2)*(-3) + 2 = -16, so a(2)*(-3) = -18 and a(1) = 6

The procedure for finding a(5), a(6) and a(7) is exactly the same.

3 0

3 years ago

The 2th term of The A.P is 7 and 9th term is 28, Find The comon difference and The first term.

Radda [10]

Answer:

difference = 3, first term = 4

Step-by-step explanation:

given, a2 = 7

a9 = 28

wkt, a2 = a + d = 7

a9 = a + 8d = 28

- 7d = - 21

therefore d = 3

and wkt, d = a2 - a

a = 7 - 3 = 4

HOPE THIS HELPS

8 0

3 years ago

Solve the equation by using the Properties of Equality. 9x – 3 = 42

Naya [18.7K]

Step-by-step explanation:

9x-3=42

9x=42+3

9x=45

9x/9=45/9

x=5

3 0

3 years ago

At 10 A.M. a plane leaves Boston, Massachusetts, for Seattle, Washington, a distance of 3000 mi. One hour later a plane leaves S

Reil [10]

Answer:

The plane from Seattle will pass the plane from Boston after 4.5 hours of its departure from the Seattle.

Step-by-step explanation:

Plane-1 = Boston, Massachusetts - Seattle, Washington at 10:00 AM

Plane-2= Seattle, Washington - Boston, Massachusetts at 11:00 AM

Speed of plane-1 = 300 mile/hour

Distance covered by plane-1 in 1 hour = 300 mile/h × 1 h = 300 mile

Distance between plane-1 and plane 2 after 1 hour :

= 3000 mile - 300 mile = 2700 mile

Let the distance covered by plane-1 after 1 hour be x in t time where it will pass plane-2.

Let the distance covered by plane-2 be y in t time where it will pass plane-1.

x + y = 2700 ...[1]

Speed of plane-1 = 300 mile/hour

$300 mile/h=\frac{x}{t}$ ..[2]

Speed of plane-2 = 300 mile/hour

$300 mile/h=\frac{y}{t}$ ..[3]

Putting value of t from [2] in [3];

$t=\frac{x}{300 mile/h}$

$300 mile/h=\frac{y}{\frac{x}{300 mile/h}}$

$\frac{x}{300 mile/h}=\frac{y}{300 mile/h}$

x = y

In [1] put x = y

y + y = 2700 miles

2y = 2700 miles

y = 1,350 mile

For the value of t, put the value of y in [3]:

$t=\frac{1,350 mile}{300 mile/h}=4.5 hour$

The plane from Seattle will pass the plane from Boston after 4.5 hours of its departure from the Seattle.

5 0

3 years ago

Solve 20x + 5y = 15 for y​

Solve 20x + 5y = 15 for y