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Sergeeva-Olga [200]
3 years ago
5

Find the area of the given shape.

Mathematics
1 answer:
Lyrx [107]3 years ago
8 0

Answer:

9

Step-by-step explanation:

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Six students are to be seated in a row of 6 chairs. if three of thses students must be seated together, how many ways could this
liraira [26]
Students : A B C D E F
3 of them (A, B, & C) must be seated together

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4 0
3 years ago
Read 2 more answers
I don’t understand this can you pls help me, i’m slow so i kinda need help
Anarel [89]

Answer:

they both have the letter L

they both have the letter A

they both have the letter B

they both have the letter M

hope this helps

please like and Mark as brainliest

3 0
4 years ago
The table and graph both represent the same relationship. which equation also represents that relationship?
kow [346]

Answer:

I think it's y= 2x

Step-by-step explanation:

For every number in y, x increases by 2

4 0
3 years ago
Read 2 more answers
Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes
yaroslaw [1]

Answer:

\frac{y^{2}}{25}-\frac{x^{2}}{3}=1

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: (0,-\sqrt{28}),(0,\sqrt{28})

eje conjugado = 2\sqrt{3}

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

de los focos podemos obtener que:

c=\sqrt{28}

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b=\sqrt{3}

podemos utilizar la siguiente fórmula para obtener a:

c^{2}-a^{2}=b^{2}

si despejamos a en la ecuación obtenemos lo siguiente:

a=\sqrt{c^{2}-b^{2}}

ahora podemos sustituir los valores:

a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}

a=\sqrt{28-3}

a=\sqrt{25}

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1

\frac{y^{2}}{25}+\frac{x^{2}}{3}=1

si graficamos la hipérbola, queda como en el documento adjunto.

7 0
3 years ago
Can someone help me with this
MA_775_DIABLO [31]

Answer:

what is that i dont answering this sorry

4 0
3 years ago
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