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4 years ago

Help I need the answers immediately

Mathematics

1 answer:

Vikki [24]4 years ago

4 0

Answer:

linear pair

Step-by-step explanation:

the sum of linear pair angles is 180 degree.

so if we apply 16 in place of x in both equations and add them we get 180

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Find the area of a triangle

lana66690 [7]

Answer: 68

Step-by-step explanation:

4 0

3 years ago

Type the correct answer in each box. Use numerals instead of words. Consider the equation below. x/h+1=-2 The value of x in term

arlik [135]

Answer:

x = -3h

x = -12

Step-by-step explanation:

Given equation is $\frac{x}{h}+1=-2$

To find the value of x in terms of h we will solve the expression to isolate x on one side of the equation.

by subtracting 1 from both the sides of the equation,

$\frac{x}{h}+1-1=-2-1$

$\frac{x}{h}=-3$

Multiplying 'h' on both the sides of the equation,

$(\frac{x}{h})\times h = (-3)h$

x = -3h

If h = 4,

x = (-3)(4)

x = -12

4 0

3 years ago

Which relation is a function?

uysha [10]

B, because nothing repeats.

4 0

3 years ago

Find the LCM of 4 and 9 A. 9 B. 35 C. 72 D. none of the above

Vitek1552 [10]

B is the answer becuase it’s 35 and that should be correct

7 0

3 years ago

Read 2 more answers

BD−→− bisects ∠ABC such that m∠ABD = (4x−5)∘ and m∠DBC = (3x+2)∘.

Rzqust [24]

Answer:

$\angle ABC=(46)^{\circ}$

Step-by-step explanation:

Given: BD bisects $\angle ABC$

$\angle ABD=(4x-5)^{\circ}\\\angle DBC=(3x+2)^{\circ}$

To find: $\angle ABC$

Solution:

A bisector of an angle divides it into angles of equal measures.

As BD bisects $\angle ABC$ , $\angle ABD=\angle DBC$

Put $\angle ABD=(4x-5)^{\circ}\,,\,\angle DBC=(3x+2)^{\circ}$

$\angle ABD=\angle DBC\\(4x-5)^{\circ}=(3x+2)^{\circ}\\4x-3x=2+5\\x=7^{\circ}$

So,

$\angle ABD=(4x-5)^{\circ}=(4(7)-5)^{\circ}=(28-5)^{\circ}=(23)^{\circ}\\\angle DBC=(3x+2)^{\circ}=(3(7)+2)^{\circ}=(21+2)^{\circ}=(23)^{\circ}$

$\angle ABC=\angle ABD+\angle DBC\\=(23)^{\circ}+(23)^{\circ}\\=(46)^{\circ}$

3 0

3 years ago

Help I need the answers immediately​

Help I need the answers immediately