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earnstyle [38]
3 years ago
9

During which phase in erythrocyte development does the color of hemoglobin overcome the color of the stained ribosomes?

Biology
1 answer:
Sphinxa [80]3 years ago
7 0

Answer:

The correct answer is - phase 2.

Explanation:

Erythropoiesis or the development of the erythrocytes is the process to which the development of the  erythrocyte cells from the bone marrow to the mature RBC. The development of these cells involved the three phases.

During second phase involves the differentiation of the precursors of the three different type of erythrocytes that are polychromatophilic, proerythroblasts, and orthochromatic erythroblasts. It also includes building up the color of the hemoglobin that overwhelms the color of ribosomes that is blue color.

Thus, the correct answer is - phase 2.

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A major disturbance that the ecosystem was able to recover completely from. ____________________________________________________
icang [17]

Complete Question:

I made the grass diseased. This caused all of the populations above it (rabbit, snake, and hawk) to rapidly decrease over the 12 month period

(a) A major disturbance that the ecosystem was able to recover completely from __________

(b) A major disturbance that caused the ecosystem to stabilize at a new equilibrium ____________

(c) A major disturbance that caused the ecosystem to completely collapse __________

ANSWER:

(a) reducing the hawks to nearly zero

(b) removing all of the hawks

(c) removing all the diseased.

Explanation:

(a) reducing the hawks to nearly zero will cause low depletion of the producer (plants) and this will allow the plant to grow (without visible depletion) over a period of time.

(b) for the ecosystem to stabilize at a new equilibrium, the tertiary consumer (hawks) will be totally removed from the ecosystem. Since there's no tertiary consumer to checkmate the density of other components of the food chain, it will make it form a balanced ecosystem.

(c) for ecosystem to collapse, it's important to note that the removal of the producer (plants) will be bring about the loss of the ecosystem. Since, their is no manufacturer of food, the primary consumer (rabbit) in the food chain will be starved and overtime the rabbits will be wiped out and this will caused the loss of secondary and tertiary consumer in the long run.

ALREADY A BRAINLY

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How do mutations impact genetic variation?
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3 years ago
Assess the importance or value of having decomposers in the food web
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3 years ago
An additional gene, gene W, was also examined. A test cross was made between true-breeding EEWW flies and EEWW flies. The result
Debora [2.8K]

This question is incorrect but here is the correct question below;

An additional gene,gene W was also examined. a test cross was made between true breeding EEWW flies and eeww flies. The resulting F₁ generation was then crossed with eeww flies. 100 offspring in the F₂ generation were examined and it was discovered that the E and W genes were not linked.

Which is the correct genotype of the F₂ offspring if the genes were linked and if the genes were not linked?

a) Linked: 50% EeWw and 50% eeww; not linked: 25% EeWw, 25% Eeww, 25% eeWw and 25% eeww.

b) Linked: 25% Eeww, 50% eeWw; not linked:parental genotypes EeWw and eeww.

c) Linked genotypes (EeWw and eeww) and recombinant genotype ( Eeww & eeWw) in the F₂ generation are nearly the same irrespective of their linkage.

d) Linked: mostly with parental genotypes, Eeww and eeWw; unlinked: 25% EeWw and eeww with 75% Eeww and eeWw.

Answer:

a) Linked: 50% EeWw and 50% eeww; not linked: 25% EeWw, 25% Eeww, 25% eeWw and 25% eeww.

Explanation:

a test cross was made between true breeding EEWW flies and eeww flies

If EEWW self crossed, we have the following ( EW, EW, EW, EW)

Also, for eeww, we have ( ew, ew, ew, ew)

                   

                    EW                   EW                     EW                   EW

ew               EWew               EWew               EWew               EWew      

ew               EWew               EWew               EWew               EWew

ew               EWew               EWew               EWew               EWew

ew               EWew               EWew               EWew               EWew

All offspring are  (EWew)

The question goes further by saying "The resulting F₁ generation was then crossed with eeww flies".

And we are asked to find the correct genotype of the F₂ offspring if the genes were linked and if the genes were not linked

∴

To determine  the offsprings of the linked genes we need to go by the definition and understand what linked genes are: Linked genes are genes that are physically close together on the same chromosomes. Effect of recombinantion on linked genes, results in gene swaps which occur in chromosomes that are homologous.

Having said that; If  EWew × eeww

we have;                 EW   &   ew    ×    ew  &    ew

           EW               ew

ew       EeWw          eeww

ew       EeWw          eeww

offspring that

are linked in   ⇒     EeWw    EeWw     &      eeww      eeww

F₂   will be

\frac{1}{2} = 50% of EeWw of the total 100 offspring in the F₂ cross

\frac{1}{2} = 50% of eeww of the total 100 offspring in the F₂ cross

∴ Linked genes =  50% EeWw and 50% eeww.

For unlinked genes; If  EWew × eeww

if rearrangement occurs in EWew  and EWew self crossed, we have ( EW,Ew,eW,ew) as the traits needed for the unlinked gene F₂ crossing.

Also ewew will be (ew, ew, ew, ew).

                       EW                    Ew                    eW                    ew

ew                  EeWw               Eeww                eeWw                eeww

ew                  EeWw               Eeww                eeWw                eeww

ew                  EeWw              Eeww                 eeWw                eeww

ew                  EeWw              Eeww                 eeWw                eeww

We have the following results for the unlinked genes

\frac{1}{4} = EeWw  25% of the total 100 offspring in the F₂ cross

\frac{1}{4} = Eeww   25% of the total 100 offspring in the F₂ cross

\frac{1}{4} = eeWw   25% of the total 100 offspring in the F₂ cross

\frac{1}{4} = eeww    25% of the total 100 offspring in the F₂ cross

∴ not linked: 25% EeWw, 25% Eeww, 25% eeWw and 25% eeww.

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