PLZ HELP...

Is a rectangle with curved angles a polygon

Alik [6]

A polygon must have at least 3 sides, but a curved angle isn't a side. This would result in you getting an oval. In short, it would not be a polygon. Hope this helps!

3 0

3 years ago

Question 7 il pont) (2 +377)(2 – 377)

Elden [556K]

Answer:

142125

Step-by-step explanation:

Since we given two brackets to solve we will have to take the step by step procedure

So let's solve the question

(2+377)(2-377)

Let's start with the first bracket

(2+377)

It will give us 379

So let's solve the second bracket

(2-377)

It will give us -375

So back to the question

(379)(-375)

142125

So the final answer is 142125

3 0

3 years ago

Match each circular flower bed on the left to its circumference and its area on the right. Some answer options on ti

user100 [1]

Answer:

Flower bed A has circumference = 31 feet, area = 79 feet²

Flower bed B has circumference = 38 feet, area = 113 feet²

Step-by-step explanation:

* Lets revise the rules of the circumference and the area of the circle

- The circumference of the circle = 2πr

- The Area of the circle = πr²

- r is the radius of the circle and it is half the diameter of the circle

# Flower bed A has a diameter 10 feet

∵ The radius = 1/2 the diameter

∴ The radius = 1/2 × 10 = 5 feet

∵ The circumference = 2πr

∴ The circumference = 2 × π × 5 = 31.42 ≅ 31 feet

∵ The area = πr²

∴ The area = π (5)² = 78.54 ≅ 79 feet²

* Flower bed A has circumference = 31 feet, area = 79 feet²

# Flower bed B has a radius 6 feet

∵ The circumference = 2πr

∴ The circumference = 2 × π × 6 = 37.70 ≅ 38 feet

∵ The area = πr²

∴ The area = π (6)² = 113.10 ≅ 113 feet²

* Flower bed B has circumference = 38 feet, area = 113 feet²

* These answers not in the choices

8 0

3 years ago

What is the difference? StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction Sta

katovenus [111]

Answer:

The option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is $\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore $\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Step-by-step explanation:

Given problem is StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction

It can be written as below :

$\frac{x}{x^2-16}-\frac{3}{x-4}$

To solve the given expression

$\frac{x}{x^2-16}-\frac{3}{x-4}$

$=\frac{x}{x^2-4^2}-\frac{3}{x-4}$

$=\frac{x}{(x+4)(x-4)}-\frac{3}{x-4}$ ( using the property $a^2-b^2=(a+b)(a-b)$ )

$=\frac{x-3(x+4)}{(x+4)(x-4)}$

$=\frac{x-3x-12}{(x+4)(x-4)}$ ( by using distributive property )

$=\frac{-2x-12}{(x+4)(x-4)}$

$=\frac{-2(x+6)}{(x+4)(x-4)}$

$\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore $\frac{x}{x^2-16}-\frac{3}{x-4}=\frac{-2(x+6)}{(x+4)(x-4)}$

Therefore the option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct

That is $\frac{-2(x+6)}{(x+4)(x-4)}$

5 0

3 years ago

Read 2 more answers

Divide 81 ft in the ratio 5 :4

Mumz [18]

Answer:

Rr = 51 : 68

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers