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3 years ago

Find the x-intercepts for the quadratic function y= -1/2(x+3)^2 +4

Mathematics

1 answer:

irina1246 [14]3 years ago

8 0

Answer:

x= -3 +√2 ≈ -0.1716, and x = - 3 -2√2 ≈ -5.8284

Step-by-step explanation:

y= -1/2(x+3)² +4

For x -intercept, y = 0.

0 = - 1/2(x+3)² + 4 /*(-2)

0 = (x+3)² - 8

(x+3)² = 8

√(x+3)² = +/-√8

x+3 = +/-√8

x = - 3+/- 2√2

x= -3 +√2 ≈ -0.1716, and x = - 3-2√2 ≈ -5.8284

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Greeley [361]

Answer:

See explanation

Step-by-step explanation:

ASA Postulate (Angle-Side-Angle):

If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

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∠X≅∠Z (given)
XY≅ZY (given)
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3 years ago

3(X + 8) + 5x What’s the answer

11111nata11111 [884]

Answer:

8x+24

Step-by-step explanation:

Solve

3 times x = 3x

3 time 8 = 24

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Combine like terms

3x+5x=

8x+24

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3 years ago

Read 2 more answers

Oliver has music lessons in Monday Wednesday and Friday.Each lesson is 3/4 of an hour Oliver says he will have lessons for three

Hoochie [10]

Oliver is incorrect because if he were correct he would learn for 2 hours and 15 minutes because, 45 minutes * 3= 2:15 minutes.

4 0

3 years ago

If 13 = 4.5 -5k what is the value of k

USPshnik [31]

Answer:

K = negative 1.7

Step-by-step explanation:

4.5- 13 = -8.5

-8.5/5 = -1.7

4.5 - 5(-1.7) = 13

Hope this helped

7 0

3 years ago

Find an equation perpendicular to x=1 and passing through (8,-9)

valina [46]

Answer:

$y=-9$

Step-by-step explanation:

We want to find an equation of a line that's perpendicular to x=1 that also passes through the point (8,-9).

Note that x=1 is a vertical line since x is 1 no matter what y is.

This means that if our new line is perpendicular to the old, then it must be a horizontal line.

So, since we have a horizontal line, then our equation must be our y-value of our point.

Our y-coordinate of our point (8,-9) is -9.

Therefore, our equation is:

$y=-9$

And this is in standard form.

And we're done!

3 0

3 years ago