d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
2.947368421 when dividing you want to make sure te numbers are divisible <span />
Answer:
1 + 1 + 2 + 2 + 3 + 3 + 4 + 4 + 5 + 5 + 6 + 6 + 7 + 7 + 8 + 8 + 9 + 9 + 10 + 10 - 90 = 20
Step-by-step explanation:
Answer:
12.9
Step-by-step explanation:
Given data
Give the expression
F(t)=8.50(1.15)^3
Let us solve the term in the bracket
F(t)=8.50*1.520875
F(t)=12.9
Hence the final answer is 12.9
