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3 years ago

Y2-y1 and y=me+b Plzz help me with this

1 answer:

3 0

Well if you have the coordinates (2,2) and (4,4) you plug in the y from the second cords for y2

So it would be 4-2/4-2 and 2/2 equals 1
1 would be the m in y=MX+b
Then plug one set of coords in y=MX+b
2=1x+b

I know it's confusing to understand but I tried lol

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The graph of y=-3x+ 2 is:

Alexeev081 [22]

Answer:

Step-by-step explanation:

This is a linear function whose slope is -3 and whose y-intercept is (0, 2). Answer A is correct.

5 0

3 years ago

let a = (a1, a2) and b = (b1, b2) and c = (c1,c2) be three non zero vectors. if a1b2 - a2b1 is not equal to 0. then show three a

Ksenya-84 [330]

Consider the contrapositive of the statement you want to prove.

The contrapositive of the logical statement

p ⇒ q

¬q ⇒ ¬p

In this case, the contrapositive claims that

"If there are no scalars α and β such that c = αa + βb, then a₁b₂ - a₂b₁ = 0."

The first equation is captured by a system of linear equations,

$\begin{cases}c_1 = \alpha a_1 + \beta b_1\\ c_2 = \alpha a_2 + \beta b_2\end{cases}$

or in matrix form,

$\begin{pmatrix}c_1\\c_2\end{pmatrix} = \begin{pmatrix}a_1&b_1\\a_2&b_2\end{pmatrix}\begin{pmatrix}\alpha\\\beta\end{pmatrix}$

If this system has no solution, then the coefficient matrix on the right side must be singular and its determinant would be

$\begin{vmatrix}a_1&b_1\\a_2&b_2\end{vmatrix} = a_1b_2-a_2b_1 = 0$

and this is what we wanted to prove. QED

3 0

3 years ago

Which equation has no solution?

Sergeu [11.5K]

Do each equation individually and compare if they are the same end answer in each question. which ever one is unequal than that is the answer

3 0

2 years ago

Pls help

joja [24]

Given:

Minni is arranging 3 different music CDs in a row on a shelf.

To find:

The sample space for the arrangement of a jazz CD (J), a pop CD (P), and a rock CD (R).

Solution:

We know that the total number of ways to arrange n items is n!.

Minni is arranging 3 different music CDs in a row on a shelf. So, the total number of ways is:

$3!=3\times 2\times 1$

$3!=6$

The sample space for the arrangement of a jazz CD (J), a pop CD (P), and a rock CD (R) is:

{JPR, JRP, PJR, PRJ, RJP, RPJ}

Therefore, the required sample space is {JPR, JRP, PJR, PRJ, RJP, RPJ}.

5 0

3 years ago

Rina is making a nut mixture to sell at the local farmers' market. She mixes 6 pounds of pecans with a nut mixture that is 70% p

Marat540 [252]

So the best way to do these is concentration1 (%) × volume1 = concentration2 × volume2
Or C1V1 + C2V2 = C3V3, where C1 = 100% (bc ALL pecans), V1 = 6 lbs, C2 = 70%, C3 = 82%:
100%×6 + 70%×v2 = 82%×(6+v2)
100%=1.00, 70%=.7, 82%=.82
note: if none is poured out then v3 = v1+v2
6 + .7v2 = .82 (6+v2)
6 + .7v2 = 4.92 + .82v2
6 + .7v2 -.7v2 = 4.92 + .82v2 -.7v2
6 = 4.92 + .12v2
6-4.92 = 4.92-4.92 + .12v2
1.08 = .12v2
.12v2/.12 = 1.08/.12
v2 = 9 lbs
that's only v2!!!

For the final poundage, we need v3:

v3 = 6 + v2 = 6 + 9 = 15 lbs

7 0

2 years ago