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swat32
4 years ago
7

Y2-y1 and y=me+b Plzz help me with this

Mathematics
1 answer:
mestny [16]4 years ago
3 0
Well if you have the coordinates (2,2) and (4,4) you plug in the y from the second cords for y2

So it would be 4-2/4-2 and 2/2 equals 1
1 would be the m in y=MX+b
Then plug one set of coords in y=MX+b
2=1x+b

I know it's confusing to understand but I tried lol
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What is 2 + 2 - 1 = ????
Snowcat [4.5K]
2 + 2 - 1 is 3. lol.
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4 years ago
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What does collinear mean
storchak [24]
Lying in the same straight line i think..

5 0
3 years ago
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Consider the quadratic function f(x) = -x^2 + 1x + 12. Determine the following: (enter all numerical answers as integers, fracti
vovikov84 [41]

Answer and Explanation:

Given : The quadratic function f(x)=-x^2+x+12

To find : Determine the following ?

Solution :

The x -intercept are where f(x)=0,

So, -x^2+x+12=0

Applying middle term split,

-x^2+4x-3x+12=0

-x(x-4)-3(x-4)=0

(x-4)(-x-3)=0

x=4,-3

The x-intercepts are (4,0) and (-3,0).

The smallest x-intercept is x=-3

The largest x-intercept is x=4

The y -intercept are where x=0,

So, f(0)=-(0)^2+0+12

f(0)=12

The y-intercept is y=12.

The quadratic function is in the form, y=ax^2+bx+c

On comparing, a=-1 , b=1 and c=1 2

The vertex of the graph is denote by (h,k) and the formula to find the vertex is

For h, The x-coordinate of the vertex is given by,

h=-\frac{b}{2a}

h=-\frac{1}{2(-1)}

h=\frac{1}{2}

For k, The y-coordinate of the vertex is given by,

k=f(h)

k=-h^2+h+12

k=-(\frac{1}{2})^2+\frac{1}{2}+12

k=-\frac{1}{4}+\frac{1}{2}+12

k=\frac{-1+2+48}{4}

k=\frac{49}{4}

The vertex of the function is (h,k)=(\frac{1}{2},\frac{49}{4})

The x-coordinate of the vertex i.e. x=-\frac{b}{2a} is the axis of symmetry,

So, x=-\frac{b}{2a}=\frac{1}{2} (solved above)

The axis of symmetry is x=\frac{1}{2}.

4 0
4 years ago
Background Layout Theme Transition 2 A hot air balloon travels up to 7500 feet. After exploring the sky for a few hours it desce
son4ous [18]

Answer:

No.

Step-by-step explanation:

This is incorrect because the hot air balloon traveled up to 7500 feet. The distance descended cannot be greater than 7500 feet. Joe's expression tells us that the hot air ballon descended 10500 feet. He is incorrect because 10500 > 7500.

5 0
3 years ago
Please Help if you can!! I also have more questions in my profile!
bixtya [17]

Answer:

(0, 9), (0, 0), (0, 1)

Step-by-step explanation:

Hope it helps you in your learning process.

3 0
3 years ago
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