Given: Heat given to mercury (Q) = 100 J
Mass of mercury (m) = 80 g = 80 × 10⁻³ kg
Specific Heat capacity of mercury (c) = 138 J/kg°C
Let the rise of temperature be Δt
Formula Used: Q = mcΔt
Here, all alphabets are in their usual meanings.
Calculation:
Q = mcΔt
or, Δt = Q / mc
or, Δt = 100 J /[(80 × 10⁻³ kg)×(138 J/kg°C)]
or, Δt = 9.058 °C
or, Δt = 9.1 °C
Hence, the required increase in temperature will be 9.1 °C.
Answer:
The mass of the baked loaf will be less than the dough.
Explanation: When heat is applied to food substance or products like the one pound the substance or material gains a higher temperature, the increase in temperature causes moisture inherent or added to the product in this case the one pound dough to be lost, the one pound dough prepared at room temperature, once it is placed inside the oven at 350 degrees Fahrenheit it will lose moisture in the form of vapor to the environment as noticed in the aroma, the moisture lost will eventually reduce it mass/weight (kilograms or grams) by some percentage or quantities(kilograms or grams)
Answer:
A. 9280.78 moles.
B. 37123.12 g.
Explanation:
We'll begin by calculating the volume of the spherical balloon. This can be obtained as follow:
Diameter (d) = 6 m
Radius (r) = d/2 = 6/2 = 3 m
Pi (π) =3.14
Volume (V) =?
V = 4/3πr³
V = 4/3 × 3.14 × 3³
V = 4/3 × 3.14 × 27
V = 113.04 m³
Next, we shall convert 20°C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 20°C
T(K) = 20°C + 273
T(K) = 293 K
Next, we shall convert 200 KPa to Pa. This can be obtained as follow:
1 KPa = 1000 Pa
Therefore,
200 KPa = 200 KPa × 1000 Pa / 1 KPa
200 KPa = 2×10⁵ Pa
A. Determination of the number of mole of He in the spherical balloon.
Volume (V) = 113.04 m³
Temperature (T) = 293 K
Pressure (P) = 2×10⁵ Pa
Gas constant (R) = 8.314 m³Pa/Kmol
Number of mole (n) =?
PV = nRT
2×10⁵ × 113.04 = n × 8.314 × 293
22608000 = n × 2436.002
Divide both side by 2436.002
n = 22608000 / 2436.002
n = 9280.78 moles
B. Determination of the mass of He.
Mole of He (n) = 9280.78 moles
Molar mass of He = 4 g/mol
Mass of He =?
Mass = mole × molar mass
Mass of He = 9280.78 × 4
Mass of He = 37123.12 g
The second one, the third one, and the last one...i'm not sure about the fourth one...
how many answers can u give?