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3 years ago

___ acceleration occurs when an object speeds up

2 answers:

6 0

The acceleration that leads to the increase in the speed of the object is called as Positive acceleration.

Explanation:

The acceleration of a body is defined as the amount of change taking place in the magnitude of the velocity of the body in every second. The acceleration of the body is a vector quantity as it requires the direction along with the magnitude of change in the speed of the body.

If the acceleration of the body is acting in the direction opposite to the direction of motion of the body, then the acceleration tends to decrease the speed of the body and it is called as deceleration.

Whereas if the acceleration of a body is in the direction same as that of the direction of motion of the body, then the acceleration of the body increases the speed of the body and this acceleration is termed as the positive acceleration of the body.

Therefore, the acceleration of an object that tends to speed up the object must be acting in the direction same as the direction of motion of the body and therefore it is termed as the positive acceleration of the body.

Thus, The acceleration that leads to the increase in the speed of the object is called as Positive acceleration.

Learn More:

1. Transnational kinetic energy brainly.com/question/9078768.

2. Motion under friction brainly.com/question/7031524.

3. Conservation of momentum brainly.com/question/9484203

Answer Details:

Grade: High School

Subject: Physics

Chapter: Acceleration

Keywords:

acceleration, rate of change, velocity, speed, increase, per second, direction, opposite, motion, along, speed up.

AleksandrR [38]3 years ago

3 0

Explanation:

Acceleration is defined as the change in velocity over time.

When there is an increment or increase in the magnitude of velocity of a moving body then it is known as positive acceleration.

Whereas when there is a decrease in magnitude of velocity of a moving body then it is known as negative acceleration.

Thus, we can conclude that positive acceleration occurs when an object speeds up.

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Answer:

a magnet that retains its magnetic properties in the absence of an inducing field or current

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3 years ago

If the water in a lake is everywhere at rest, what is the pressure as a function of distance from the surface? The air above the

Rudiy27

Answer:

101325 + 10055.25h

h = 10.1 m

Explanation:

the pressure at sea level = 1 atm = 101325 Pa

density of sea water = 1025 kg/ m^(3)

pressure due to fluid height = pgh

Absolute pressure = 101325 + 1025*9.81*h

= 101325 + 10055.25h

where h= 0 at sea level at increases downwards

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h = 10.1 m

Explanation:

7 0

3 years ago

What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8~\mathrm{m/s^2}g=9.8 m/s 2 ) towards the Eart

Wittaler [7]

Answer:

The centripetal acceleration as a multiple of $g=9.8 m/s^{2}$ is $1.020x10^{-3}m/s^{2}$

Explanation:

The centripetal acceleration is defined as:

$a = \frac{v^{2}}{r}$ (1)

Where v is the velocity and r is the radius

Since the person is standing in the Earth surfaces, their velocity will be the same of the Earth. That one can be determined by means of the orbital velocity:

$v = \frac{2 \pi r}{T}$ (2)

Where r is the radius and T is the period.

For this case the person is standing at a latitude $71.9^{\circ}$ . Remember that the latitude is given from the equator. The configuration of this system is shown in the image below.

It is necessary to use the radius at the latitude given. That radius can be found by means of trigonometric.

$\cos \theta = \frac{adjacent}{hypotenuse}$

$\cos \theta = \frac{r_{71.9^{\circ}}}{r_{e}}$ (3)

Where $r_{71.9^{\circ}}$ is the radius at the latitude of $71.9^{\circ}$ and $r_{e}$ is the radius at the equator ( $6.37x10^{6}m$ ).

$r_{71.9^{\circ}}$ can be isolated from equation 3:

$r_{71.9^{\circ}} = r_{e} \cos \theta$ (4)

$r_{71.9^{\circ}} = (6.37x10^{6}m) \cos (71.9^{\circ})$

$r_{71.9^{\circ}} = 1.97x10^{6} m$

Then, equation 2 can be used

$v = \frac{2 \pi (1.97x10^{6} m)}{24h}$

Notice that the period is the time that the Earth takes to give a complete revolution (24 hours), this period will be expressed in seconds for a better representation of the velocity.

$T = 24h . \frac{3600s}{1h}$ ⇒ $84600s$