Question

3.

Answer 1

Answer:

4.05×10⁶ N.

Explanation:

The following data were obtained from the question:

Breadth (B) = 4 m

Length (L) = 10 m

Standard pressure (P) = 101325 Nm¯²

Force (F) =..?

Next, we shall determine the area of the wall. This can be obtained as follow:

Area (A) = length (L) × breadth (B)

A = 10 × 4

A = 40 m²

Finally, we shall determine the force exerted on one side of the wall as follow:

Standard pressure (P) = 101325 Nm¯²

Area (A) = 40 m²

Force (F) =.?

Pressure (P) = Force (F) /Area (A)

101325 = F/40

Cross multiply

F = 101325 × 40

F = 4.05×10⁶ N.

Therefore, a force of 4.05×10⁶ N was exerted on one side of the wall.