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Soloha48 [4]
3 years ago
10

Can someone please help me with this one question please??

Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0
((5x2)+5.5+(6x3)+6.5+(7x5)+(7.5x4)+(8x4))/20
137/20
= 6.85
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What is (2y + 14.6m + 3.8) – (34.8m + 15.6 + 2y)
zhenek [66]

Answer:

-20.2m -11.8

Step-by-step explanation:

(2y + 14.6m + 3.8) – (34.8m + 15.6 + 2y)

Distribute the minus sign

(2y + 14.6m + 3.8) – 34.8m - 15.6 - 2y

I like to line them up vertically

   2y + 14.6m + 3.8

– 2y   -34.8m - 15.6

------------------------------

       -20.2m -11.8

4 0
3 years ago
What maths is used in locating a falling aircraft on the radar?
kvasek [131]

Answer:

I believe its Calculus

Step-by-step explanation:

6 0
3 years ago
A city has 7,204 recycling bins. The city gives half of the recycling bins to its citizens. The rest of the recycle bins are div
tekilochka [14]

Answer:156.6 i think i could be wrong tho

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
If you choose two cards at random from a deck of 52 cards, what is the probability that it is two diamonds?
kari74 [83]
<h3>Answer:</h3>

1/17 or 0.0588 (without replacement)

<h3>Step-by-step explanation:</h3>

To answer this question we need to know the following about a deck of cards

  • A deck of cards contains 4 of each card (4 Aces, 4 Kings, 4 Queens, etc.)
  • Also there are 4 suits (Clubs, Hearts, Diamonds, and Spades).
  • Additionally, there are 13 cards  in each suit (Clubs/Spades are black, Hearts/Diamonds are red) .

In this case, we are required to determine the probability of choosing two diamonds.

  • There are 13 diamonds in the deck.
  • Assuming, the cards were chosen without replacement;

P(Both cards are diamonds) = P(first card is diamond) × P(second card is diamond)

P(First card is diamond) = 13/52

If there was no replacement, then after picking the first diamond card, there are 12 diamond cards remaining and a total of 51 cards remaining in the deck.

Therefore;

P(Second card is diamond) = 12/51

Thus;

P(Both cards are diamonds) = 13/52 × 12/51

                                               = 156/2652

                                              = 1/17 or 0.0588

Hence, the probability of choosing two diamonds at random (without replacement) is 1/17 or 0.0588.

5 0
4 years ago
Please help, when you give me the answer please can you put the number of the question so I know
ZanzabumX [31]
Didn't answer all because I got lazy and I think you should try and do the rest yourself. Did this in 5 mins, try putting more effort into your homework. This is basic mathematics.

8 0
3 years ago
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