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gavmur [86]
3 years ago
5

PLEASE HELP!!!!!!!!!!!!!!!!!!According to the periodic table, a single carbon atom had a mass of 12.11 amu. what is he mass of a

single carbon atom in grams. PS THIS IS INTRO TO MOLES AND ALL I KNOW IS AVOGADROS MOLE THING WAS 6.02x10^23
Chemistry
1 answer:
Oxana [17]3 years ago
3 0
A carbon 12 atom is 1.99200e-23 grams
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The rate (in mg carbon/m3/h) at which photosynthesis takes place for a species of phytoplankton is modeled by the function p = 1
maxonik [38]

The given function is:

P = 120 i / (i^2 + i + 9)

or

P = 120 i (i^2 + i + 9)^-1

<span>The maxima point is obtained by taking the 1st derivative of the function then equating dP / di = 0:</span>

dP / di = 120 (i^2 + i + 9)^-1 + (-1) 120 i (i^2 + i + 9)^-2 (2i + 1)

setting dP / di =0 and multiplying whole equation by (i^2 + i + 9)^2:

0 = 120 (i^2 + i + 9) – 120i (2i + 1)

Dividing further by 120 will yield:

i^2 + i + 9 – 2i^2 – i = 0

-i^2 + 9 =0

i^2 = 9

<span>i = 3      (ANSWER)</span>

Therefore P is a maximum when i = 3

Checking:

P = 120 * 3 / (3^2 + 3 + 9)

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4 years ago
Which of the following represents the equation for volume?
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L× W×H

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What are the elements and number of atoms in the compound c6h12o6?
VARVARA [1.3K]
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Which of the following types of electromagnetic radiation have higher frequencies than visible light and which have shorter freq
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Answer:

3,4,1 and 6,5,2

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Radio waves

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3 years ago
The volume of a gas held at constant temperature varies indirectly as the pressure of the gas. If the volume of a gas is 1200 cu
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Answer:

Volume of the gas at 500 mm Hg pressure is 960 cm^{3}

Explanation:

Let's assume the gas behaves ideally.

According to combined gas law for an ideal gas-

                  \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

Where P_{1} and  P_{2} are initial and final pressure of the gas respectively.  V_{1} and  V_{2} are initial and final volume of the gas respectively.  T_{1} and  T_{2} are initial and final temperature of the gas in kelvin respectively.

Here T_{1} = T_{2}, V_{1} = 1200 cm^{3}, P_{1} = 400 mm Hg, P_{2} = 500 mm Hg

So, V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}

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Hence volume of the gas at 500 mm Hg pressure is 960 cm^{3}

3 0
4 years ago
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