Question

find the equation of a straight line joining the points (6,9) and (4,7). Please help im bad at mathematic :( and please do a calculation too.

Answer 1

Answer:

$\boxed{y=x+3}$

Step-by-step explanation:

Solve for slope first.

The slope can be found through 2 points.

$slope=\frac{change \: in \: y}{change \: in \: x}$

$slope=\frac{7-9}{4-6}$

$slope=\frac{-2}{-2}$

$slope=1$

Using slope-intercept form.

$y=mx+b\\m=slope\\b=y \: intercept$

$y=1x+b$

Let x = 6 and y = 9.

$9=1(6)+b$

$9-6=b$

$3=b$

$y=1x+3$

Answer 2

Answer:

y = x+3

Step-by-step explanation:

First step is to find the slope

m = ( y2-y1)/(x2-x1)

   = ( 7-9)/(4 - 6)

   = -2 / -2

  = 1

The we can put is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

y = 1x+b

Putting in one of the points

9 = 1*6+b

Subtracting 6

9-6 = b

3=b

y = 1x+3

y = x+3