Let p and w represent the speed of the plane and the speed of the wind, respectively.
.. speed = distance/time
.. p +w = 720/3 = 240
.. p -w = 720/4 = 180
Add the two equations to eliminate w.
.. 2p = 420
.. p = 210
.. w = p -180 = 30
The speed of the wind is 30 mph.
The speed of the plane in still air is 210 mph.
Answer:
Option 3. 71 ft. is the distance between B and top of the hill.
Step-by-step explanation:
Let the height of the hill is h ft and the distance of A from the hill be x ft and distance from B to hill is y.
It is given distance between A and B is 45 ft. ∠BAO = 65° and ∠ABO = 80°.
We have to find the distance of B from the top of the hill.
Now from ΔACO
From ΔBCO
h = 5.67x
Now h = 5.67x = 2.14(45-x)
5.67x = 96.3 - 2.14x
2.14x + 5.67x = 96.3
7.81x = 96.3
x = 96.3/7.81 = 12.33 ft
Therefore
Therefore 71 ft is the distance between B and the top of the hill.
Answer:
Here is the link to find the answer. Good Luck!
Step-by-step explanation:
bit. ly/3a8Nt8n
Answer:
45 apps
Step-by-step explanation:
1 minute has 60 seconds
If 12 seconds equals to 9 apps
60 seconds equals to x apps
Cross multiplying
Therefore, Dean downloads 45 apps in 1 minute