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Oksana_A [137]
2 years ago
12

PLEASE HELP!!!!!!! What is the slope of the line?

Mathematics
1 answer:
iren [92.7K]2 years ago
8 0

Answer:

Slope = 1

Step-by-step explanation:

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Solve each system by elimination.
strojnjashka [21]

Answer:

y = -1, x = -2

Step-by-step explanation:

First, multiply the top equation by 2 to make 3x become 6x:

6x - 8y = -4

Second, multiply the bottom equation by 3 to make -2x become -6x:

9y - 6x = 3

Add the two equations together, and you get:

y = -1

Plug in y as -1 into the first or second equation:

3x - 4(-1) = -2

OR

3(-1) - 2x = 1

x = -2

5 0
3 years ago
Find the coordinates of a point that divides the directed line segment PQ in the ratio 5:3. A) (2, 2) B) (4, 1) C) (–6, 6) D) (4
Yuri [45]

Answer:

The answer is explained below

Step-by-step explanation:

The question is not complete we need point P and point Q.

let us assume P is at (3,1) and Q is at (-2,4)

To find the coordinate of the point that divides a line segment PQ with point P at (x_1,y_1) and point Q at (x_2,y_2) in the proportion a:b, we use the formula:

x-coordinate:\\\frac{a}{a+b}(x_2-x_1)+x_1 \\\\While \ for\ y-coordinate:\\\frac{a}{a+b}(y_2-y_1)+y_1

line segment PQ  is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:

x-coordinate:\\\frac{5}{5+3}(-2-3)+3 \\\\While \ for\ y-coordinate:\\\frac{5}{5+3}(4-1)+1

4 0
3 years ago
Phoebe took a survey of her classmates' favorite sport. The results are in the table below:
olga55 [171]

Answer:

.14

Step-by-step explanation:

7 0
3 years ago
7th grade math help me pleaseeee
Eduardwww [97]

Answer:

4x + 5y = 20

Step-by-step explanation:

4x + 5y = 20

5y = -4x + 20      (Subtract 4x to isolate 5y. Put the 4x in front of the 20)

y = -\frac{4}{5}x + 4         (Divide all by 5 to isolate y)

And then it's done and in slope-intercept form

-1< -\frac{4}{5} < 0        or -\frac{4}{5} is greater than -1 but less than 0

I hope this helped :)

3 0
3 years ago
The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th
choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

f_x(x) = \dfrac{1}{1500} ; o \le x \le   \  1500

The function of the insurance is:

I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \  \ \ \ 250 \le x \le 1500}} \right.

Hence, the variance of the insurance can also be an account forum.

Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2

here;

E[I(x)] = \int f_x(x) I (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}

\dfrac{5}{12} \times 1250

Similarly;

E[I^2(x)] = \int f_x(x) I^2 (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}

\dfrac{5}{18} \times 1250^2

∴

Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]

Finally, the standard deviation  of the insurance payment is:

= \sqrt{Var(I(x))}

= 1250 \sqrt{\dfrac{5}{48}}

≅ 404

4 0
3 years ago
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