Answer:
A(n)=130+13(n-1) ; 86
Step-by-step explanation:
Here is the sequence
130,143,156,169.......
the first term denoted by a is 130 and the common difference denoted by d is second term minus first term
143 - 130 = 13
Hence a=130 and d = 13
Now we have to evaluate to 13th term.
The formula for nth term of any Arithmetic Sequence is
A(n) = a+(n-1)d
Hence substituting the values of a ,and d get
A(n)=130+13(n-1)
To find the 13th term , put n = 13
A(13)=130+13*(13-1)
= 130+13*12
= 130+156
A(13) = 286
X- Alyssa's goal
*100%=45%
=
36*100=45x
3600=45x /:45
x=80
Her goal was 80 bags of peanuts
Negative 1 because 3 x 3 is 9 and -2 x 5 is -10. Therefore 9-10= negative 1
Add 2x + 5 and 4x - 7
Then you isolate the variable or “get rid of” the numbers that re stopping you from getting “x”.
By doing the inverse operation.
If you add ___ you subtract ____ it form itself
If you subtract ___ you add ____ To itself.
So you Cancel out by getting rid of the other numbers.
Same thing with multiplying and dividing.
If you multiply ____ you divide___ but don’t divide “x”
Only the integer.
If you divide _____ you multiply ____ it
Reeeee.............tooooooooo
