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Lena [83]
3 years ago
6

Determine the volume of the triangular prism so below. A. 558 1/8 cubic inches B. 279 1/16 C. 142 5/16 D. 284 5/8

Mathematics
1 answer:
Murljashka [212]3 years ago
4 0

I had the same question as you and the answer is D

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What ordered pair is represented by the plotted point?
bezimeni [28]
B. (-7,4)
hope it helps
4 0
3 years ago
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Analyze ady Porter is buying t ride tickets at the county fair. He receives 3 tickets for every dollar, d, that he spends. Which
Vanyuwa [196]

Answer:

The answer is below

Step-by-step explanation:

An independent variable is a variable that does not dependent on other variables. It is the input variable.

A dependent variable is a variable that is dependent on other variables. The dependent variable depends on the independent variable. It is the output variable.

Since porter receives 3 tickets for every dollar, this means the number of ticket is dependent on the money he spend. Therefore the money he spends (d) is the independent variable and the tickets (t) is the dependent variable.

4 0
2 years ago
How.many grams equals 25 killograms
34kurt

Answer:

Step-by-step explanation:

1 kilogram = 1000 grams

since we need to know 25 kilograms you can do

25 x 1000

giving us 25,000

4 0
3 years ago
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A tank contains 3,000 L of brine with 15 kg of dissolved salt. Pure water enters the tank at a rate of 30 L/min. The solution is
Shalnov [3]

Answer:

Step-by-step explanation:

Volume of tank is 3000L.

Mass of salt is 15kg

Input rate of water is 30L/min

dV/dt=30L/min

Let y(t) be the amount of salt at any time

Then,

dy/dt = input rate - output rate.

The input rate is zero since only water is added and not salt solution

Now, output rate.

Concentrate on of the salt in the tank at any time (t) is given as

Since it holds initially holds 3000L of brine then the mass to volume rate is y(t)/3000

dy/dt= dV/dt × dM/dV

dy/dt=30×y/3000

dy/dt=y/100

Applying variable separation to solve the ODE

1/y dy=0.01dt

Integrate both side

∫ 1/y dy = ∫ 0.01dt

In(y)= 0.01t + A, .A is constant

Take exponential of both side

y=exp(0.01t+A)

y=exp(0.01t)exp(A)

exp(A) is another constant let say C

y(t)=Cexp(0.01t)

The initial condition given

At t=0 y=15kg

15=Cexp(0)

Therefore, C=15

Then, the solution becomes

y(t) = 15exp(0.01t)

At any time that is the mass.

5 0
3 years ago
Can any one help me
emmainna [20.7K]
I think you set up the equation like this

$2.50x+5

I hope I helped sorry if I didn't.

8 0
3 years ago
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