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dolphi86 [110]
3 years ago
7

I need help with math please

Mathematics
1 answer:
ASHA 777 [7]3 years ago
7 0

Answer:

greater than cb and less than ab ig

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A pair of vertical angles have the measure of 2y + 5 degrees + 4y degrees what is the value of y​
timama [110]

Answer:

The value of y s 2.5

Step-by-step explanation:

Vertical angles are always equal to one another. In this case, we can find the angles by setting the two values equal and solving algebraically.

2y + 5 = 4y

5 = 2y

2.5 = y

7 0
3 years ago
What is the image of point (4, 5) after a counterclockwise rotation of 270º about the origin?
tia_tia [17]
The answer is (5, -4).
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3 years ago
32 and 2.56 what is the unit rate
Serggg [28]
12.5 

I hope this helped.

5 0
3 years ago
The scale on the architectural plans for a new house is 1 in. equals 4 ft. Find the length and width (in ft) of a room that meas
Oksi-84 [34.3K]

Answer: the actual length and width of the room is 24ft by 36ft

Step-by-step explanation:

The scale on the architectural plans for a new house is 1 in. equals 4 ft. This means that every 1 inch on the on the architectural plan represents 4 feet on the actual building.

Therefore, if the length of the room as measured on the drawing is 6 inches, the actual length of the room will be

6 × 4 = 24 feet

Also, if the width of the room as measured on the drawing is 9 inches, the actual width of the room will be

9 × 4 = 36 feet

8 0
3 years ago
A B R and P are four points on a circle with centre 0. A O R and C are four points on a different circle. The two circles inters
Slav-nsk [51]

Answer:

x° = ∠OBR = ∠ABC (base angles of a cyclic isosceles trapezoid)

Step-by-step explanation:

APRB form a cyclic trapezoid

∠APO  = x° (Base angle of an isosceles triangle)

∠OPR  = ∠ORP (Base angle of an isosceles triangle)

∠ORB = ∠OBR (Base angle of an isosceles triangle)

∠APO + ∠OPR + ∠OBR = 180° (Sum of opposite angles in a cyclic quadrilateral)

Similarly;

∠ORB + ∠ORP + x°  = 180°

Since ∠APO = x° ∠ORB = ∠OBR and ∠OPR  = ∠ORP we put

We also have;

∠OPR = ∠AOP = ∠BOR (Alternate interior angles of parallel lines)

Hence 2·x° + ∠AOP = 180° (Sum of angles in a triangle) = 2·∠OBR + ∠BOR

Therefore, 2·x° = 2·∠OBR, x° = ∠OBR = ∠ABC.

6 0
3 years ago
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