The speed of plane is 105 miles per hour and speed of wind is 28 miles per hour.
Step-by-step explanation:
Given,
The distance traveled by plane = 1463 miles
The trip with the wind took 11 hours.
The trip took 19 hours against the wind.
Let,
s be the speed of plane and w be the speed of wind.
Therefore;
Speed with the wind = s+w
Speed into the wind = s-w
We know that;
Distance = Speed * Time
Therefore;
Equation for trip taken with wind.
1463 = 11(s+w)
Dividing both sides by 11
Equation for trip taken into the wind
1463 = 19(s-w)
Dividing both sides by 19
Adding Eqn 1 and 2
Dividing both sides by 2
Putting s=105 in Eqn 1
The speed of plane is 105 miles per hour and speed of wind is 28 miles per hour.
Rewrite Vl=I0wLcos(wt+pi/2) as a function of sin wt<span> - 3433279. ... get answers with explanations.</span>
The c+5 should represent the five more cds that he has thats more than julias
Answer:
Step-by-step explanation:
x + 2y = 14 ...............(1)
6x + 3y = 21 ..............(2)
Solve for x in equation 1
When x + 2y = 14
Therefore x = 14 - 2y ...................(3)
Now put equation 3 in equation 2 and solve
6x + 3y = 21 .............(2)
6(14 - 2y) + 3y = 21
Open the bracket and resolve
84 - 12y + 3y = 21
-9y + 84 =21
Now collect the like terms
-9y + 84 = 21
-9y = 21 - 84
-9y = -63
Divide through by -9 to get y
y = -63/-9
y = 7
Substitute for y in equation( 3 )to x
x= 14 - 2y............(3)
So, x = 14 - 2(7)
x = 14 - 14
x = 0.
Therefore x = 0 and y = 7
Check: From equation (1)
x + 2y = 14
Now, put x = 0 and y = -2
Therefore, 0 +2(7) =14
0 +14 = 14
