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3 years ago

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Aleesia has a box of 52 muffins. She wants to put out plates that each have the same number of muffins. What is one possible way

Aleesia could put an equal number of muffins on each plate so there are no muffins leftover

1 answer:

Brums [2.3K]3 years ago

8 0

Answer:

4 muffins per plate (13 plates)

Other answers are possible. See below

========================================================

Explanation:

The factors of 52 are: 1, 2, 4, 13, 26, 52

If Aleesia picks any of those values, then she will divide the muffins up equally.

For example, if she puts 4 muffins per plate, then that means she'll have 13 plates since 4*13 = 52.

Or she could put 2 muffins per plate to get 26 plates (because 2*26 = 52).

Side note: A prime factor tree might be helpful.

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The line represented by the equation 2y - 3x = 4 has a slope of.....

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4 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

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4 years ago

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Answer:

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Step-by-step explanation:

The average rate of change of f(x) in the close interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

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