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ryzh [129]
3 years ago
14

A bearing, measured at 1.234 inches with a caliper, must be replaced. Since the bearings are sized in 64ths of an inch, find the

closest fractional size.
Mathematics
1 answer:
Ganezh [65]3 years ago
7 0
We have
1.234 in-----> 1+(0.234) in

we know that
1/64=0.015625
so
0.234/0.015625=14.98-----> 15
15/64-----> 0.234

therefore
1.234 in is equal to -----------> 1 15/64 in

the answer is
1 15/64 in
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Please answer quick! God bless.
mario62 [17]

Answer:

I d k

Step-by-step explanation:

5.75x10=57.50

57.5+11.5=69(nice)

69+5.75= 74.75

74.75+5.75=80.5

80.5+5.75= 86.25

86.25+5.75=92

basically this formula should help

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7 0
3 years ago
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1. Write an algebraic expression for the sum of three coins and c coins.
Juliette [100K]

Answer:

1 Is A

2 is B

3 is A

4a is D

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3 years ago
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6: x= 45 and it is acute

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Read 2 more answers
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y = ln(3x),
denis23 [38]

Using the disk method, the volume is obtained with the integral

\displaystyle\pi\int_{y=1}^{y=5}\left(\frac{e^y}3\right)^2\,\mathrm dy=\frac\pi9\int_1^5e^{2y}\,\mathrm dy

The radius of each disk is given by the horizontal distance from the axis of revolution, x=0, to the logarithmic curve which we can write as a x(y):

y=\ln(3x)\implies e^y=e^{\ln3x}=3x\implies x=\dfrac{e^y}3

Then the volume of one such disk is \pi x(y)^2.

The volume of the entire solid would be

\displaystyle\frac\pi9\int_1^5e^{2y}\,\mathrm dy=\frac\pi{18}\int_1^52e^{2y}\,\mathrm dy=\frac\pi{18}\int_1^5e^{2y}\,\mathrm d(2y)

=\dfrac\pi{18}\left(e^{10}-e^2\right)

7 0
3 years ago
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