What is 0.99755 + 1.22 + 3.0005 + 0.0012

1 answer:

4 0

The answer to your question is 5.21925

0.99755+1.22=2.21755
2.21755+3.0005=5.21805
5.21805+0.0012=5.21925

Hope this helps! :)

You might be interested in

D is the midpoint of AC. If AD = 2x + 6 and DC = 4x-7, what is the length of DC?

DENIUS [597]

A----------D----------C

AD = 2x + 6
DC = 4x - 7

the midpoint D splits AC into 2 equal parts....therefore, AD = DC

2x + 6 = 4x - 7
2x - 4x = -7 - 6
-2x = - 13
x = -13/-2
x = 6.5

DC = 4x - 7......4(6.5) - 7 = 19 <===
AD = 2x + 6.....2(6.5) + 6 = 19

4 0

3 years ago

Emily is observing the velocity of a cyclist at different times. After four hours, the velocity of the cyclist is 14 km/h. After

lina2011 [118]

Assume that Emily starts from rest so that the velocity is zero at 0 hours.

Define the function v(t) for velocity in km/h, and t in hours.

Part A
From t=0 to t=4, v changes from 0 to 14.
Let v(t) = mt + b
The slope is
m = 14/4 = 3.5, and the y-intercept is
b = 0.
Therefore
v(t) = 3.5t, for 0 ≤ t ≤ 4

Fromt=4 to t=9, changes from 14 to 4.
Let v(t) = mt + b
The slope is
m = (4 - 14)/(9 - 4) = -2
Therefore
v = -2t + b
When t=4, v=14, therefore
14 = -2*4 + b = -8 + b
22 = b
v(t) = -2t + 22, for 4 < t ≤ 9.

Answer:
The equation for the velocity is
v(t) = 3.5t, 0 ≤ t ≤ 4
= -2t + 22, 4 < t ≤ 9

Part B
The equation for velocity is a piecewise function that is graphed as shown below. If we assume that the second part of the equation is valid at t=10, then
v(10) = -2*10 + 22 = 2 km/h