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alexandr402 [8]
3 years ago
8

What do you think would happen if there was more glucose (sugar) than available NAD+? Explain.

Biology
1 answer:
EleoNora [17]3 years ago
8 0

Answer:

n people who have developed diabetes, glucose builds up in the blood, resulting in hyperglycemia. ... And, too much sugar in the bloodstream can cause other types of damage to body tissues, which can increase the risk of heart disease and stroke, kidney disease, vision problems, and nerve problems in people with diabetes.

Explanation:

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What are the thin fibers of the human nervous system called?
netineya [11]

Answer:

C.) nerves

Explanation:

A nerve is a thin bundle of fibers that connects the body to the brain and receives and transmits messages. I hope this helps! ^-^

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2 years ago
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HELP PLEASE ILL GIVE BRAINLIEST
My name is Ann [436]

Answer:

external

Explanation:

<em>Through the process of photosynthesis, plants use the sun's energy to make sugars to function. External means from an outside force, while internal means from within. Since the sun isn't inside a plant, they gather it from outside, thus it's external.</em>

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3 years ago
PLEASE HELP ( REALLY EASY ) Since we cannot see magnetic forces, what do scientists and engineers use to show them on a magnetic
sergij07 [2.7K]

A compass  

The Earth's magnetic field, provided by the magnet in a compass, shows the direction of the north and south poles.

ANSWER MADE BY AN AI

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3 years ago
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Refer to the regions A, B, C, and D shown on the U.S. map below.
LuckyWell [14K]

Answer:

from A to C

Explanation:

from A to C

8 0
3 years ago
A performer, seated on a trapeze, is swinging back and forth with a period of 8.90 s. If she stands up, thus raising the center
iren2701 [21]

Answer:

8.800s

Explanation:

When the performer swings, she oscillates in SHM about Lo of the string with time period To = 8.90s.

First, determine the original length Lo, where for a SHM the time period is related to length and the gravitational acceleration by the equation

T = 2π×√(Lo/g)..... (1)

Let's make Lo the subject of the formulae

Lo = gTo^2/4π^2 ..... (2)

Let's put our values into equation (2) to get Lo

Lo = gTo^2/4π^2

= (9.8m/s^2)(8.90s)^2

------------------------------

4π^2

= 19.663m

Second instant, when she rise by 44.0cm, so the length Lo will be reduced by 44.0cm and the final length will be

L = Lo - (0.44m)

= 19.663m - 0.44m

= 19.223m

Now let use the value of L into equation (1) to get the period T after raising

T = 2π×√(L/g)

= 2π×√(19.223m/9.8m/s^2)

= 8.800s

7 0
3 years ago
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