Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Answer 1

Condition One

x^2 = 0

sqrt(x^2) = sqrt(0)

x = 0

Condition Two

4x - 3 = 0

4x = 3

x = 3/4

Condition 3

5x - 1 = 0

5x = 1

x = 1/5 or

x = 0.2

A graph certainly helps with this problem. The places where this function crosses the x axis are the places which are the answers to your question. They are marked with a small dot.

Answer 2

$x^2(4x-3)(5x-1)=0\iff x^2=0\ \vee\ 4x-3=0\ \vee\ 5x-1=0\\\\x^2=0\to\boxed{x=0}\\\\4x-3=0\ \ \ |+3\\4x=3\ \ \ |:4\\\boxed{x=\dfrac{3}{4}}\\\\5x-1=0\ \ \ |+1\\5x=1\ \ \ |:5\\\boxed{x=\dfrac{1}{5}}\\\\Answer:\ x=0\ or\ x=\dfrac{3}{4}\ or\ x=\dfrac{1}{5}$