For this case what you should do is use the following trigonometric relationship:
sin (x) = C.O / h
Where
x: angle
C.O: opposite leg
h: hypotenuse
Substituting the values we have:
sen (60) = long / h
sen (60) = 3 / h
h = 3 / sin (60)
h = 3.46
Answer:
h = 3.46
Answer: false
Step-by-step explanation:
If f and g are increasing on I, this implies that f' > 0 on I and g' > 0 on I. That is both f' and g' have a positive slope. However,
Using product rule;
(fg)' = fd(g) + gd(f)
(fg)' = f * g' + f' * g
and although it is given that g' and f' are both positive we don't have any information about the sign of the values of the functions themselves(f and g). Therefore, if at least one of the functions has negative values there is the possibility that the derivative of the product will be negative. For example;
f = x, g = 5x on I = (-5, -2)
f' = 1 and g' =5 both greater than 0
f and g are both lines with positive slopes therefore they are increasing, but f * g = 5x^2 is decreasing on I.
Answer:
child's ticket = 4.75 adult ticket=10.75.
Step-by-step explanation:
The cost of an adult ticket is 6 more than that of a child ticket, so will be denoted by c+6. Now, we are told that the cost of four child tickets and two adult tickets is 40.50, so we can put this in an equation and solve for c:
(c+6)+(c+6)+c+c+c+c=40.50
6c+12=40.50
6c=28.50
c=4.75
Therefore the cost of a child's ticket (c) is 4.75 and the cost of an adult ticket (c+6) is 10.75.
