All categories

4 years ago

9. The inverse of an ordered pair on a graph is its reflection across the line y = x.

Mathematics

1 answer:

Serga [27]4 years ago

5 0

Answer:

9. Always true

10. Always true

11. Never true

12. Always true

13. Always true

14. Never true

Step-by-step explanation:

An inverse is defined as the reflection across the line y=x. Algebraically this means that x and y switch place in the inverse equation and in the coordinate points of a function.

A line will always give a line.

Example: y = 2x -2

Inverse: x = 2y -2 which when rearranged is y = 1/2 x +1.

This also means that the slope if greater than 1 for the function will have a slope less than 1 for its inverse.

You might be interested in

Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

(x, y) ----> (x + 2, y - 3) please help this is my final

ipn [44]

slide right 2 and down 3

OPTION B is the correct answer.

7 0

3 years ago

Simplify 3(a+4b)=3a+12b

MAXImum [283]

Step-by-step explanation:

3(a+4b)

3×a+3×4b=3a+12b

3a+12b=3a+12b

7 0

3 years ago

Read 2 more answers

PLEASEEEEEEEEEE HELPPPPPPPPPPPPp<br> It is in the picture.

In-s [12.5K]

Answer: D

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the end behavior of the function f(x) = −3x4−x3 + 2x2 + 4x + 5? Select one: a. Up on the left, up on the right b. Up on

lubasha [3.4K]

The graph falls to the left and falls to the right.

7 0

3 years ago