6.665 grams of the 13 grams remain after 8 hours.
<h3>How much of a 13 gram sample of iron-52 would remain after 8 hours?</h3>
The decay equation for the 13 grams of iron-52 is:
Where N is the amount of iron-52, and t is the time in years.
Where we used the fact that the half-life is exactly 8.3 hours.
Now, the amount that is left is given by N(8h), so we just need to replace the variable t by by 8 hours, so we get:
So 6.665 grams of the 13 grams remain after 8 hours.
If you want to learn more about half-life:
brainly.com/question/11152793
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Answer:
AngleWUT =38°, option 2
Step-by-step explanation:
We have three rays passing through U. A ray is set extend in one direction with one fixed point.
We have UW ray bisecting VUT.As the ray bisects the angle between VUW and WUT would be same .
Given angles are (4x+6)° and (6x-10)°.
As these angles are equal
AngleWUT = (6x – 10)°
and x is 8 so on substituting AngleWUT =38°.
Answer: 
Step-by-step explanation:
1. You know that:
- The roped-off area whose width is represented with <em>x,</em> it is created around a rectangular museum.
- The dimensions of the rectangular museum are: 30 ft by 10 ft.
- The combined area of the display and the roped-off area is 800 ft².
2. The area of the rectangular museum can be calculated with:
Where 
is the lenght and 
is the width.
You have that the lenght and the width in feet are:
3. Let's call 
the width of the roped-off area. Then, the combined area is:
Where
4. Substitute values and simplify. Then:
Answer:
2/5
Step-by-step explanation:
5/5 = full job
3/5 = done
full job - done = remaining
5/5 job - 3/5 job
= 2/5 (remaining)
Answer:
The answer is (x,y)=(-3,-2)
Step-by-step explanation:
I used the comparison method because I dont know what type of method you needed, sorry. The methods I know would be: the Comparison Method (what I used), the Substitution Method, Elimination Method,Inverse Matrix Method, Cramer's Rule, and the Gauss-Jordan Method.
You can also rewrite this equation to 3x-y=-7 and x-y=-1.
I'm sorry, I dont know what kind of answer you're looking for. I really hope this helps.
