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Stella [2.4K]
3 years ago
5

Can somebody answer this for me, please? **_You get 20 Points_**

Mathematics
2 answers:
Archy [21]3 years ago
4 0
Here is your answer

Area of trapezoid=

\frac {1}{2} ×(sum of parallel sides)× distance between them

1. Area=\frac {1}{2}×(6.2+3.8)×7

=\frac{1}{2}×10×7

= 5×7

=35 {ft}^{2}

2. Area= \frac{1}{2}×(10.3+15.1)×12.6

= \frac{1}{2}×25.4×12.6

= 12.7×12.6

= 160.02 {in}^{2}

HOPE IT IS USEFUL
nevsk [136]3 years ago
3 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Use this formula:

Area = ((a + b)/2) x h

a is the top length

b is the bottom length

h is the vertical height

1) Substitute in the values:

((3.8 + 6.2)/2) x 7 = 35ft^2 <== this is the answer

2) Substitute in the values:

((10.3 + 15.1)/2) x 12.6 = 160.02in^2 <== this is the answer

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\  \\ &#10; (x^{a} )^{b} = x^{a*b}  \\  \\ &#10;\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } =  \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} = 
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